$ .ajaxError如何工作?

问题描述

我广泛使用$ .get，$.post和$ .getJSON，所以我想看看.ajaxError是如何工作的.我试过了...

I use $.get, $.post, and $.getJSON extensively, so I wanted to see how .ajaxError worked. I tried this...

$(document).ajaxError(function (e, xhr, options, error)
{
    console.log(e);
    console.log(xhr);
    console.log(options);
    console.log(error);
});

，我也尝试将其放入我的$(document).ready().中.然后我禁用了我的网络连接.从AJAX中的定时POST冒出了很多错误(因为它们得到了意外的响应)，并且GET瞬间返回了(缓存)，但是Firebug中没有其他内容，就像ajaxError从未出现过一样被呼叫.我究竟做错了什么?我只是再次尝试了，没有控制台日志，只是alert('foo')，再次没有任何反应.错误很多，但是ajaxError永远不会触发.

and I also tried putting it inside my $(document).ready().. And then I disabled my network connection. A slew of errors flew up from the timed POSTs in AJAX (because they were getting unexpected responses), and the GETs were coming back instantaneously (cached), but nothing else appeared in Firebug, as if ajaxError were never being called. What am I doing wrong? I just tried again with no console logs and just alert('foo'), and again nothing happened. Lots of errors, but ajaxError never firing.

推荐答案

ajaxError github.com/jquery/jquery/blob/master/src/ajax.js#L636"rel =" noreferrer>在jQuery源中可以看到.该特定功能中的响应代码被视为成功"代码；任何其他事情都是失败.

ajaxError is triggered when the actual XHR does not receive an HTTP success code from a given response from the server, as you can see in the jQuery source. The response codes in that particular function are perceived as "success" codes; anything else is a failure.

jQuery也仅分支到XMLHTTPRequest结束时以readyState为4触发ajaxError的代码(完成所有接收到的数据)，因此我认为关闭网络连接实际上会使您陷入另一种情况总共XHR条件(可能是条件2的循环?). 您也可以看到jQuery在源代码中的分支方式

jQuery also only branches to the code that triggers ajaxError when your XMLHTTPRequest winds up with a readyState of 4 (complete with all data received), so I think shutting off your network connection would actually put you in a different XHR condition altogether (possibly a loop of condition 2?). You can see how jQuery branches in the source, too.

基本上，它看起来服务器是否没有说请求失败并发送了超出该范围的代码，您可能不会看到ajaxError被触发，因为根据jQuery，它没有收到一个错误.

Basically, it looks if the server doesn't say the request failed and send back a code outside of that range above, you likely won't see ajaxError being triggered as, according to jQuery, it hasn't received an error.

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