运算符优先级

问题描述

对于int a = 5，为什么a ++ * ++ a = 36因为*从左到右行为而++ a pre -increments a所以我们应该有5x7 = 35。我的书都说++优先于*。

For int a=5, why does a++ * ++a = 36 because * acts left-to-right and ++a pre-increments a so we should have 5x7=35. My books all say that ++ has precedence over *.

推荐答案

我不完全确定，但是++只会在语句结束后递增，而++ a会在语句之前递增a。


所以，既然我们在声明中有++ a，a = 6

所以a ++ * ++ a = 36


并在该语句之后，a = 7.

I''m not entirely sure, but a++ will only increment after the end of the statement, while ++a will increment a before the statement.

So, since we have ++a in the statement, a = 6

so a++ * ++a = 36

and after that statement, a = 7.

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