本文介绍了JQueryUI-如果将可拖放区域缩小,则可拖动元素将被拖放到多个可拖放区域的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试将element拖放到可放置区域.假设我有多个具有相同class的可放置区域,并且为此class编写了drop事件处理程序.

如果我使用-webkit-transform:scale(0.3,0.3);缩小可放置区域,则放置事件行为很奇怪.在将可拖动元素附加到一个可放置区域之一之前,该放置发生在多个可放置区域上.

我认为此问题是由于使用scale引起的,但是我不知道如何解决它.谷歌搜索也无济于事.

我为 DEMO 设置了一个小提琴.

这是我的代码

脚本

var click = {
    x: 0,
    y: 0
}; // used for recording mouse cords

$('document').ready(function(event){
    for(var i = 0 ; i <= 72 ; i++)
    {
        $('<div></div>').attr({'class':'drop_zone','id':'drop_'+i}).appendTo($('.main_container'));
    }
    $('.drop_zone').each(function(index,element){
        $(this).attr('id','drop_'+index);
    })
    $('.draggable').draggable();
    $('.draggable').on('dragstart',function(event,ui){
        $('#droppable_area_ids').html('');
        click.x = event.clientX;
        click.y = event.clientY;
    })
    $('.draggable').on('drag',function(event,ui){
        var zoom = 0.3;
        var original = ui.originalPosition;

        ui.position = {
            left: (event.clientX - click.x + original.left) / zoom,
            top:  (event.clientY - click.y + original.top ) / zoom
        };
    })
    $('.draggable').on('dragend',function(event,ui){
        click.x = 0;
        click.y = 0;
    })
    $('.drop_zone').droppable({
        tolerance: 'pointer',
        accept: ".draggable"
    });
    $('.drop_zone').on('drop',function(event,ui){
        console.log('dropped on ' + $(this).attr('id'));
        $('.draggable').css({'position':'absolute','top':'0px','left':'0px'}).appendTo($(this));
        $(this).parent().css('z-index',10);
        $('#droppable_area_ids').html($('#droppable_area_ids').html() + ' , ' + $(this).attr('id'));
    })
})

样式

*
{
    padding:0px;
    margin: 0px;
}
.main_container
{
    -webkit-transform: scale(0.3,0.3);
    width: 1000px;
    height: 1000px;
    background-color: #efefef;
    position: absolute;
    top: -200px;
    left: -220px;
}
.drop_zone
{
    background-color: #7e7e7e;
    width:100px;
    height:100px;
    position: relative;
    margin-left: 10px;
    margin-top: 10px;
    float: left;
}
.draggable
{
    background-color: #262626;
    width:100px;
    height: 200px;
    z-index: 100;
}
#droppable_area_ids
{
    position: absolute;
    top:100px;
    left:100px;
    width:100%;
    float:left;
}

HTML

<div class="main_container">
    <div class="draggable"></div>
</div>
<div id="droppable_area_ids"></div>

任何帮助将不胜感激.

编辑

这恰好是> JQUERY已知问题 ,似乎他们不会在不久的将来修复它.如果有人为此采取了变通办法,那将会有很大的帮助.

解决方案

找到了一种解决方法,将其发布在这里,以防万一.

我不得不修改jquery-ui.js.

m[i].proportions = { width: m[i].element[0].offsetWidth, height: m[i].element[0].offsetHeight};

m[i].proportions = { width: m[i].element[0].offsetWidth*scaleFactor, height: m[i].element[0].offsetHeight*scaleFactor };

其中scaleFactor初始化为1,然后在您的javascript代码中将其更改为css-transform的值,即,如果您使用-webkit-transform:scale(0.3,0.3),请将scaleFactor设置为0.3,则bingo完成!

使用更改后的jquery-ui.js文件更新了小提琴

http://jsfiddle.net/P4FMr/4/

I am trying to drag and drop and element onto a droppable area. Let's say that I have multiple droppable areas with the same class and I have written a drop event handler for this class.

If I scale down my droppable areas using -webkit-transform:scale(0.3,0.3);, the drop event acts weird. The drop happens onto muliple droppable zones before the draggable element gets attached to one of the droppable areas.

I assume that this issue is because of using the scale but I don't have any idea how to fix it. Googling didn't help either.

I have set up a fiddle for DEMO.

Here is my code

THE SCRIPT

var click = {
    x: 0,
    y: 0
}; // used for recording mouse cords

$('document').ready(function(event){
    for(var i = 0 ; i <= 72 ; i++)
    {
        $('<div></div>').attr({'class':'drop_zone','id':'drop_'+i}).appendTo($('.main_container'));
    }
    $('.drop_zone').each(function(index,element){
        $(this).attr('id','drop_'+index);
    })
    $('.draggable').draggable();
    $('.draggable').on('dragstart',function(event,ui){
        $('#droppable_area_ids').html('');
        click.x = event.clientX;
        click.y = event.clientY;
    })
    $('.draggable').on('drag',function(event,ui){
        var zoom = 0.3;
        var original = ui.originalPosition;

        ui.position = {
            left: (event.clientX - click.x + original.left) / zoom,
            top:  (event.clientY - click.y + original.top ) / zoom
        };
    })
    $('.draggable').on('dragend',function(event,ui){
        click.x = 0;
        click.y = 0;
    })
    $('.drop_zone').droppable({
        tolerance: 'pointer',
        accept: ".draggable"
    });
    $('.drop_zone').on('drop',function(event,ui){
        console.log('dropped on ' + $(this).attr('id'));
        $('.draggable').css({'position':'absolute','top':'0px','left':'0px'}).appendTo($(this));
        $(this).parent().css('z-index',10);
        $('#droppable_area_ids').html($('#droppable_area_ids').html() + ' , ' + $(this).attr('id'));
    })
})

THE STYLE

*
{
    padding:0px;
    margin: 0px;
}
.main_container
{
    -webkit-transform: scale(0.3,0.3);
    width: 1000px;
    height: 1000px;
    background-color: #efefef;
    position: absolute;
    top: -200px;
    left: -220px;
}
.drop_zone
{
    background-color: #7e7e7e;
    width:100px;
    height:100px;
    position: relative;
    margin-left: 10px;
    margin-top: 10px;
    float: left;
}
.draggable
{
    background-color: #262626;
    width:100px;
    height: 200px;
    z-index: 100;
}
#droppable_area_ids
{
    position: absolute;
    top:100px;
    left:100px;
    width:100%;
    float:left;
}

THE HTML

<div class="main_container">
    <div class="draggable"></div>
</div>
<div id="droppable_area_ids"></div>

Any help will be appreciated.

EDIT

This happens to be a KNOWN ISSUE WITH JQUERY and seems that they won't be fixing it in the near future. If anybody has done a workaround for this, it'll be of great help.

解决方案

Found a workaround , posting it here just in case it helps anyone else.

I had to modify jquery-ui.js.

m[i].proportions = { width: m[i].element[0].offsetWidth, height: m[i].element[0].offsetHeight};

to

m[i].proportions = { width: m[i].element[0].offsetWidth*scaleFactor, height: m[i].element[0].offsetHeight*scaleFactor };

where scaleFactor is initialized to 1 and is changed in your javascript code to the value of css-transform , i.e., If you use -webkit-transform:scale(0.3,0.3) , set the scaleFactor to 0.3 and bingo , you are done!

Updated fiddle using the changed jquery-ui.js file

http://jsfiddle.net/P4FMr/4/

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08-15 21:06