在iOS中发送HTTP PATCH请求（Objective-c）

问题描述

我正在使用REST API，其中一个api是 PATCH ，我试图使用以下代码调用它，但它会抛出错误，而同样的api在<$ c中工作$ c> Postman client。

I am consuming REST APIs, one of the api is PATCH, i tried to invoke it using following code but it throws error, while same api works in Postman client.

+ (NSURLSessionTask *)callPATCHAPIWithAPIName:(NSString *)apiName andCompletionHandler:(void(^)(id result, NSInteger responseCode, NSError *error))completionHandler
{
    NSString *getURL = @"192.168.1.100/UpdateDeviceInfo/iPhone6/OS 9.2";
    NSURL *URL = [NSURL URLWithString:getURL];
    NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:URL];

    NSURLSessionConfiguration *sessionConfiguration = [NSURLSessionConfiguration defaultSessionConfiguration];
    sessionConfiguration.timeoutIntervalForRequest = 45.0f;

    NSURLSession *session = [NSURLSession sessionWithConfiguration:sessionConfiguration];

    // Create Data from request
    NSData *requestData = [NSData dataWithBytes: [@"" UTF8String] length:[@"" length]];

    [request setHTTPMethod:@"PATCH"];
    [request setValue:[NSString stringWithFormat:@"%lu", (unsigned long)[requestData length]] forHTTPHeaderField:@"Content-Length"];

    [request setHTTPBody:requestData];

    NSURLSessionDataTask *task = [session dataTaskWithRequest:request
                                            completionHandler:
                                  ^(NSData *data, NSURLResponse *response, NSError *error)
                                  {
                                      NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *) response;

                                      NSInteger responseCode = [httpResponse statusCode];
                                      NSLog(@"response Code : %ld",(long)responseCode);
                                  }];

    [task resume];
    return task;
}

我在查询字符串中传递参数，而不是在请求正文中。虽然同样的事情是在 Postman 客户端& Android。

I am passing parameters in query string, not in request body. Though same thing is working in Postman client & Android.

推荐答案

好像你在 NSString中有一个空格* getURL = @192.168.1.100 / UpdateDeviceInfo / iPhone6 / OS 9.2

我不相信网址格式支持空格！相反，如果需要空格，请确保使用 getURL = [getURL stringByAddingPercentEscapesUsingEncoding：NSUTF8StringEncoding]; 以便处理url字符串中的空格！

I do not believe whitespaces are supported in url formats! Instead, if whitespaces are necessary, make sure you use getURL = [getURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; in order to handle whitespaces in url strings!

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