OR运算符用C不工作

问题描述

我不明白为什么最后的printf 在下面的code未打印255。

 字符℃;
C = C＆安培; 0;
输出（C的值为％d，（int）的三）;
INT J = 255;
C =（C |百灵）;
输出（C的值为％d，（int）的三）;
 

解决方案

在大多数实现了字符类型有符号，所以从的取值范围 - 128 到 127 。

这意味着， 11111111 （这是 255 写成二进制）等于 -1 。 （由于这是psented存储在一个价值重估$ P $）

要得到你所期望的，你需要声明 C 为 unsigned char型，就像这样：

  unsigned char型C = 0;
INT J = 255;
C =（C |百灵）;
输出（C的值为％d，（int）的三）;
 

I don't understand why the final printf in the code below is not printing 255.

char c;
c = c & 0;
printf("The value of c is %d", (int)c);
int j = 255;
c = (c | j);
printf("The value of c is %d", (int)c);

解决方案

In most implementations the char type is signed, so it ranges from -128 to 127.

This means, 11111111 (which is 255 written in binary) is equal to -1. (As it's represented as a value stored in two's complement)

To get what you expect, you need to declare c as a unsigned char, like so:

unsigned char c = 0;
int j = 255;
c = (c | j);
printf("The value of c is %d", (int)c);

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