本文介绍了使用按位运算符从32位整数检索字节的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
下面是什么问题，我现在有，我只是不明白它是如何错...
int getByte(int x, int n) {
return ((x << (24 - 8 * n)) >> (8 * n));
}
解决方案
Your shifting doesn't make any sense - first, you shift left by (24 - 8n) bits, then you shift back right by 8n bits. Why? Also, it's wrong. If n is 0, you shift x left by 24 bits and return that value. Try pen and paper to see that this is entirely wrong.
The correct approach would be to do:
int getByte(int x, int n) {
return (x >> 8*n) & 0xFF;
}
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