问题描述
在特定的 if-else
中,我必须确定给定值是否在一个范围内。条件部分如下所示:
In a particular if-else
, I have to identify if a given value falls within a range. The condition part looks like this:
else if (a==2 && b.equalsIgnoreCase("line")
&& <<Here I need to search if c falls within a range>> && d)
其中a是int,b是字符串,c是int,d是布尔值。现在,如果c落在1到8之间,则条件为真,否则为假。我怎么能这样做?
where a is int, b is string, c is int and d is a boolean. Now if c falls within 1 to 8, the condition is true, else it is false. How can I do that?
推荐答案
我认为你需要这个条件 c
I think you need you this condition for c
(c > 1 && c < 8) // 1 and 8 are exclusive
(c => 1 && c <= 8) // 1 and 8 are inclusive
完整样本
else if (a==2 && b.equalsIgnoreCase("line")
&& (c > 1 && c < 8) && d)
如果你需要检查值是否属于一组值,你需要使用 Set
,然后检查 c
属于或不属于。在您的原始问题中,它被称为范围,因此是答案。无论如何,这是你如何检查集合中的值。
If you need to check if the values belongs to a set of values, you need to use a Set
and then check if the c
belongs to that or not. In your original question, it was mentioned as a range and thus the answer. Anyways, this is how you can check a value in a set.
Integer[] arr = {1,4,9,11,13};
Set<Integer> set = new HashSet<>(Arrays.asList(arr));
...
else if (a==2 && b.equalsIgnoreCase("line")
&& (set.contains(c)) && d)
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