问题描述
我有一个类似的DataFrame:
I have a DataFrame like so:
column1 column2 column3
0 a 2 2
1 b 1 0
2 c 3 2
第3列中的值必须< =第2列中的值
Where the value in column3 is necessarily <= the value in column2
我想根据以下规则将df扩展到下面:
I want to expand df to below based on the following rules:
column1 column2 column3
0 a 1 1
1 a 1 1
2 b 1 0
3 c 1 1
4 c 1 1
5 c 1 0
- 每行都扩展为一个数字行等于其在column2中的值
- 如果其索引(相对于column1分组)的索引小于column3中原始未展开的行的值,则展开的行的column3的值等于1 。
例如:
看到column1 = a的行是e因为其column2的值等于2,所以将其x分成2行,并且由于0 <0导致两个扩展行在column3中都具有值1。 2和1 < 2。
For example:See that the row with column1=a was expanded into 2 rows because its column2 value was equal to 2, and both the resulting expansion rows have a value of 1 in column3 because 0 < 2 and 1 < 2.
请注意,由于column2的值等于3,所以column1 = c的行被扩展为3行,但是,只有前2个扩展行具有column3中的值1(再次:0
See that the row with column1=c was expanded into 3 rows because its column2 value was equal to 3, however, only the first 2 resulting expansion rows have a value of 1 in column3 (again: 0 < 2 and 1 < 2), however, the third expanded row gets a value of 0 for column3 because (yeah, yeah, yeah, this isn't kindergarten math) it is not true that 2 < 2.
我可以在第一个给定的数据帧上使用什么函数,以获得类似于第二个的结果?
What function can I use on a dataframe like the one first given, to get a result that looks like the second one?
推荐答案
np.repeat
+ 总金额
np.repeat
+ cumcount
u = pd.DataFrame(np.repeat(df.values, df.column2, axis=0), columns=df.columns)
u.assign(
column2=1,
column3=(u.column3 > u.groupby('column1').cumcount()).astype(int)
)
column1 column2 column3
0 a 1 1
1 a 1 1
2 b 1 0
3 c 1 1
4 c 1 1
5 c 1 0
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