如何在没有CALLBACK参数的情况下获取数据

如何在没有CALLBACK参数的情况下获取数据

本文介绍了不是合法的JSONP API - 如何在没有CALLBACK参数的情况下获取数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图从JSONP端点获取一些数据。看起来响应中返回了数据,但Angular仍然会抛出错误。

Im trying to grab some data from a JSONP endpoint. It looks like the data is being returned in the response but Angular nonetheless throws an error.

var url = "https://careers.icims.com/jobs-api/"

var trustedUrl = $sce.trustAsResourceUrl(url);

$http.jsonp(trustedUrl, {jsonpCallbackParam: 'jobs'}).then(function(res){

    console.log(res); // this is never executed :.(

});

我得到以下信息错误:未捕获的ReferenceError:作业未定义
at jobs-api?jobs = angular.callbacks._0:1

其中 jobs 引用我的JSONP前缀

I am getting the following error: Uncaught ReferenceError: jobs is not defined at jobs-api?jobs=angular.callbacks._0:1where jobs refers to my JSONP prefix

然而响应返回JSONP脚本:

Yet the response returns the JSONP script:

为什么会抛出此异常以及如何清除它?我在Angular 1.6.0上

Why is this exception being thrown and how can it be cleared? I am on Angular 1.6.0

推荐答案

不是合法的JSONP API



该URL的API不是

它可以带有危险的se服务:

It can be gotten with a dangerous service:

app.service("dangerousAPI", function($q) {
  this.get = get;

  function get(funcName, url) {
    var dataDefer = $q.defer();

    window[funcName] = function(x) {
      dataDefer.resolve(x);
    }

    var tag = document.createElement("script");
    tag.src = url;

    document.getElementsByTagName("head")[0].appendChild(tag);

    return dataDefer.promise;
  }
})

使用风险由您自行承担。

Use at your own risk.

angular.module("app",[])
.service("dangerousAPI", function($q) {
  this.get = get;

  function get(funcName, url) {
    var dataDefer = $q.defer();

    window[funcName] = function(x) {
      dataDefer.resolve(x);
    }

    var tag = document.createElement("script");
    tag.src = url;

    document.getElementsByTagName("head")[0].appendChild(tag);

    return dataDefer.promise;
  }
})

.run(function($rootScope, dangerousAPI) {
    var url = "https://careers.icims.com/jobs-api/";
    dangerousAPI.get('jobs',url).then(function(data) {
      $rootScope.data = data;
    })
})
<script src="//unpkg.com/angular/angular.js"></script>
  <body ng-app="app">
    <h1>Dangerous API DEMO</h1>
    <pre>{{data | json}}</pre>
  </body>

这篇关于不是合法的JSONP API - 如何在没有CALLBACK参数的情况下获取数据的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-15 12:59