如何从由popen在php中打开的进程中获取输出?

问题描述

文件a.php:

<?php
echo "abcdef";
?>

文件b.php:

<?php
$h=popen('php a.php',r);
pclose($h);
?>

问题:

我无法在控制台上看到回显结果；为什么以及如何看到它?

I can't see the echo result on console;why and how to see it?

我不想在文件b.php中这样做，例如:echo stream_get_contents($h);

I don't want to do it in file b.php like:echo stream_get_contents($h);

推荐答案

在 popen ，它确切地说明了如何做到这一点:

Check the second example in the documentation on popen, it shows exactly how to do that:

<?php
error_reporting(E_ALL);

/* Add redirection so we can get stderr. */
$handle = popen('/path/to/executable 2>&1', 'r');
echo "'$handle'; " . gettype($handle) . "\n";
$read = fread($handle, 2096);
echo $read;
pclose($handle);

此代码段从stderr中读取.删除要从stdout读取的管道.

This snippet reads from stderr. Remove the pipe to read from stdout.

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