问题描述
我想找到一个角色的记忆地址，但我注意到了一些事情，我无法理解。
char name [] = {hello};
//查找内存地址这就是我所做的名字数组
cout<<名称[]的内存地址是：<<& name []< < endl;
//这个工作正常，现在我想在
名称数组中找到一个字符的内存地址
//说我想找到char h ||的内存地址char e
//所以这就是我找到的地址
cout<<名称的内存地址[0 ]是：<< &（name [0]）<< endl;
//现在这里是问题，我得到错误的结果，我得到的是你好而不是获取内存地址
//我在网上找到了这个技巧，找到了名字[0]的内存地址
cout<<的内存地址name [0]是：<<< static_cast< void>（&（name [0]）<< endl;
我不明白为什么&（name [0]）dint工作的正常方法是什么，static_cast< void>（&（name [0]）的含义是什么？它是做什么的？
请任何人用简单的语言解释一下。谢谢
I want to find the memory address of a character but i have noticed somethings and i am unable to understand it.
char name[] = {"hello"};
// to find the memory address of name array this is what i did
cout<<"The memory address of name[] is:"<<&name[]<<endl;
//this works fine and now i want to find the memory address of a character in the
name array
// say i want to find the memory address of char h || char e
//so this is what i did for finding the address
cout<<"The memory address of name[0] is:"<< &(name[0])<<endl;
//now here is the problem, i get wrong results, what i get is "hello" instead of getting the memory address
// i looked online and found this trick to find the memory address of name[0]
cout<<"the memory address of name[0] is:"<<static_cast<void>(&(name[0])<<endl;
I dont understand why the normal approach of &(name[0]) dint work and what is the meaning of static_cast<void>(&(name[0]) and what does it do?
Please can anyone explain me in simple terms. Thanks
推荐答案
char name[] = "Hello";
cout<<"the memory address of name[0] is:"<<static_cast<void*>(&name[0])<<endl;
有关不同类型演员表的更多信息（因为 static_cast 不是唯一一个），请参阅 []
For more info on different types of casts (as static_cast is not the only one) see http://www.cplusplus.com/doc/tutorial/typecasting/[^]
这篇关于如何在C ++中找到字符的内存地址？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！