如何使用python xml.etree.ElementTree解析eBay API响应?

问题描述

我正在尝试使用xml.etree.ElementTree来解析来自eBay查找API findItemsByProduct的响应.经过长时间的反复试验，我想到了这段代码，该代码可以打印一些数据:

I am trying to use xml.etree.ElementTree to parse responses from eBay finding API, findItemsByProduct. After lengthy trial and error, I came up with this code which prints some data:

import urllib
from xml.etree import ElementTree as ET

appID = 'xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx'
isbn = '3868731342'

namespace = '{http://www.ebay.com/marketplace/search/v1/services}'

url = 'http://svcs.ebay.com/services/search/FindingService/v1?' \
    + 'OPERATION-NAME=findItemsByProduct' \
    + '&SERVICE-VERSION=1.0.0' \
    + '&GLOBAL-ID=EBAY-DE' \
    + '&SECURITY-APPNAME=' + appID \
    + '&RESPONSE-DATA-FORMAT=XML' \
    + '&REST-PAYLOAD' \
    + '&productId.@type=ISBN&productId=' + isbn

root = ET.parse(urllib.urlopen(url)).getroot()

for parts in root:
    if parts.tag == (namespace + 'searchResult'):
        for item in list(parts):
            for a in list(item):
                if a.tag == (namespace + 'itemId'):
                    print 'itemId: ' + a.text
                if a.tag == (namespace + 'title'):
                    print 'title: ' + a.text

但这似乎不是很优雅，如何在不遍历所有属性并检查是否是我想要的属性的情况下获取"itemId"和"title"呢?我尝试使用 .get(namespace +'itemId')和 .find(namespace +'itemId')和 .attrib.get(namespace +'itemId')，但实际上没有任何作用.

But that seems not very elegant, how can I get the 'itemId' and 'title' without looping over all attributes and checking if it is the one I want? I tried using things like .get(namespace + 'itemId') and .find(namespace + 'itemId') and .attrib.get(namespace + 'itemId') but nothing really worked.

有人可以告诉我如何使用此API的某些python包装器来执行此操作吗?我看到了 easyBay ， ebay-sdk-python 和 pyeBay ，但我没有设法让他们中的任何一个去做我想做的事情.是否有任何值得使用的eBay python API?

Can someone maybe show me how to do this using some python wrapper for this API?I saw easyBay, ebay-sdk-python and pyeBay but I didn't manage to get any of them to do what I want. Is there any eBay python API which is worthwhile to use for this?

推荐答案

您可以使用 ElementTree .如果要获取商品，可以使用findall以及商品的路径，然后遍历商品列表:

You can use ElementTree. If you want to get the items you can use findall and the path to the items, then iterate over the list of items:

items = root.findall(namespace+'searchResult/'+namespace+'item')
for item in items:
     item.find(namespace+'itemId').text
     item.find(namespace+'title').text

要直接从根目录获取第一个itemId:

To get directly to the first itemId from the root:

root.find(namespace+'searchResult/'+namespace+'item/'+namespace+'itemId')

基本上，find方法使用XPath检索子元素下一层以上的元素.另请参见 Effbot对ElementTree中XPath支持的解释

Basically, the find method uses XPath to retrieve elements more than one level below the subelements. See also Effbot's explanation of XPath support in ElementTree

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