本文介绍了在C#中的mysql中打印所有主题的学生标记表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述


我无法在一张桌子上显示学生的成绩

表数据如下:

HiI have trouble displaying students' grades in one table
The table data is as follows:

CREATE TABLE `tb_marks` (
  `id` int(11) NOT NULL,
  `id_subject` int(11) NOT NULL,
  `code_student` int(11) NOT NULL,
  `round` varchar(50) NOT NULL,
  `mark` varchar(50) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
------------------
INSERT INTO `tb_marks` (`id`, `id_subject`, `code_student`, `round`, `mark`) VALUES
(3, 1, 2, 'first', '45'),
(2, 1, 3, 'first', '45'),
(4, 2, 2, 'first', '46'),
(5, 3, 2, 'first', '0'),
(6, 4, 2, 'first', '84'),
(7, 5, 2, 'first', '77'),
(8, 6, 2, 'first', '65');
---------------------------------
CREATE TABLE `tb_student_old` (
  `id` int(11) NOT NULL,
  `name` varchar(100) NOT NULL,
  `school` varchar(50) NOT NULL,
  `code` int(11) NOT NULL,
  `age` date DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
-------------------
INSERT INTO `tb_student_old` (`id`, `name`, `school`, `code`, `age`) VALUES
(1, 'ahmad', 'school', 0, NULL),
(2, 'noor', 'school', 0, NULL),
(3, 'salim', 'school', 0, NULL),
(4, 'emad', 'school', 0, NULL);
------------------------------------------
CREATE TABLE `tb_subject` (
  `id` int(11) NOT NULL,
  `name` varchar(50) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
------------------
INSERT INTO `tb_subject` (`id`, `name`) VALUES
(1, 'islamic'),
(2, 'arabic'),
(3, 'english'),
(4, 'math'),
(5, 'science'),
(6, 'social'),
(7, 'geographically'),
(8, 'date'),
(9, 'national');



我需要查询或编程,如下表所示:


I need the query or programming that gives me the table as follows:

SNo Student Name   islamic|arabic|english|math|science|social|geographic|Total
      1    ahmad		88	88	88	88   88	    88	    88	      8888





我尝试过:





What I have tried:

SELECT `tb_marks`.`id` , `tb_marks`.`round`, `tb_marks`.`mark` , `tb_subject`.`name` , `tb_student_old`.`name`, `tb_student_old`.`school` FROM `tb_marks` INNER JOIN `tb_subject` ON `tb_subject`.`id` = `id_subject` INNER JOIN `tb_student_old` ON `tb_student_old`.`id` = `code_student` WHERE code_student='2';
But the result was not right:

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10-28 19:32