将参数传递给正在运行的应用程序

问题描述

我正在制作图像上传器(将图像上传到图像托管网站)，但在传递参数(图像位置到已运行的应用程序)时遇到了一些问题

I am making an image uploader (upload image to image hosting website) and I'm having some issues passing an argument (image location to an already running application)

• 首先假设 MyApp.exe 一直在运行
• 每当我右键单击图像时，我都会在默认的 Windows 上下文菜单中添加一个项目，上面写着上传图像".
• 当它被点击时，它需要将位置传递给已经运行的应用程序.

我的程序.cs:

static class Program
{
    [DllImport("user32.dll")]
    static extern IntPtr FindWindow(string lpClassName, string lpWindowName);

    [DllImport("user32.dll")]
    static extern IntPtr SendMessage(IntPtr hWnd, uint Msg, UIntPtr
    wParam, IntPtr lParam);

    [DllImport("user32.dll", SetLastError = true, CharSet = CharSet.Auto)]
    static extern uint RegisterWindowMessage(string lpString);

    [STAThread]
    static void Main(params string[] Arguments)
    {
        if (Arguments.Length > 0)
        {
    //This means that the the upload item in the context menu is clicked
    //Here the method "uploadImage(string location)"
    //of the running application must be ran
        }
        else
        {
    //just start the application
            Application.Run(new ControlPanel());
        }
    }
}

请注意，ControlPanel 类没有可见的表单，由于不需要表单，因此只存在托盘图标.

Note that the ControlPanel class doesn't have a visible form, only a tray icon is present since a form is not needed.

我能得到有关如何执行此操作的任何帮助吗?

Could I get any help on how to do this?

推荐答案

我已经想通了，非常感谢发布 http://social.msdn.microsoft.com/Forums/en-US/csharpgeneral/thread/a5bcfc8a-bf69-4bbc-923d-f30f9ecf5f64 链接，这正是我要找的！

I have figured it out, so awesome thanks for the person who posted the http://social.msdn.microsoft.com/Forums/en-US/csharpgeneral/thread/a5bcfc8a-bf69-4bbc-923d-f30f9ecf5f64 link, this is exactly what I was looking for!

这是一个完整的解决方案:

Here's a the full solution:

static class Program
{
    [STAThread]
    static void Main(params string[] Arguments)
    {
        SingleInstanceApplication.Run(new ControlPanel(), NewInstanceHandler);
    }

    public static void NewInstanceHandler(object sender, StartupNextInstanceEventArgs e)
    {
        string imageLocation = e.CommandLine[1];
        MessageBox.Show(imageLocation);
        e.BringToForeground = false;
        ControlPanel.uploadImage(imageLocation);
    }

    public class SingleInstanceApplication : WindowsFormsApplicationBase
    {
        private SingleInstanceApplication()
        {
            base.IsSingleInstance = true;
        }

        public static void Run(Form f, StartupNextInstanceEventHandler startupHandler)
        {
            SingleInstanceApplication app = new SingleInstanceApplication();
            app.MainForm = f;
            app.StartupNextInstance += startupHandler;
            app.Run(Environment.GetCommandLineArgs());
        }
    }
}

非常感谢所有人，尤其是我上面提到的发布该链接的人，但我猜他删除了他的答案?

Thanks alot all, and especially the person who posted that link I mentioned above but I guess he deleted his answer?

问候，肯尼

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