本文介绍了在列表视图切换按钮,在Android的滚动屏幕时,失去其状态的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有,其中每个数据来自列表获取适配器列表视图。
在列表视图中的每一项都包含一个文本视图,切换按钮。
但是,当我滚动列表出现问题。切换按钮的选中状态改变即如果我在指数4选择切换按钮,然后滚动后,我发现,除了第四任何随机按钮被选中。
I have a list view in which each data is fetched from List adapter.Each item in list view contains a text view and toggle button.But there occurs a problem when i scroll the list. the checked state of toggle buttons change i.e if i selected a toggle button at index 4, then after scrolling i find that any random button except fourth is selected.
推荐答案
如果你仍然没有得到任何解决方案,请尝试此方法getview ..
// switchState []是一个布尔数组。
if u still doesn't get any solution pls try this getview method..// switchState[] is a boolean array .
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder holder = new ViewHolder();
// mSwitchButton = (ToggleButton) findViewById(R.id.switchButton);
if(convertView == null) {
convertView = mInflator.inflate(R.layout.settings_item_cell, parent, false);
holder.categoryName =
(TextView) convertView.findViewById(R.id.categoryType);
convertView.setTag(holder);
holder.switchButton = (ToggleButton) convertView.findViewById(R.id.switchButton);
}
else {
holder = (ViewHolder) convertView.getTag();
}
holder.switchButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
// TODO Auto-generated method stub
int index = (Integer) v.getTag();
Log.v("tag of switch============",""+index);
if(((ToggleButton) v).isChecked()) {
switchState[index] = true;
((ToggleButton) v).setButtonDrawable(R.drawable.item_selected);
}
else {
((ToggleButton) v).setButtonDrawable(R.drawable.item_deselected);
switchState[index] =false;
}
isToggleButtonClicked = true;
}
});
if(switchState[position])
holder.switchButton.setButtonDrawable(R.drawable.item_selected);
else
holder.switchButton.setButtonDrawable(R.drawable.item_deselected);
holder.categoryName.setText(categories[position]);
holder.switchButton.setTag(new Integer(position));
return convertView;
}
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