如何用新值替换散列中的所有值？ | 如何用新值替换散列中的所有值

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问题描述

假设我有一个任意嵌套的Hash code $：

  def初始化（d =零）
 self.dict = d 
结束

然后你可以减少 convert_hash

Let's say I have an arbitrarily deep nested Hash h:

h = {
  :foo => { :bar => 1 },
  :baz => 10,
  :quux => { :swozz => {:muux => 1000}, :grimel => 200 }
  # ...
}

And let's say I have a class C defined as:

class C
  attr_accessor :dict
end

How do I replace all nested values in h so that they are now C instances with the dict attribute set to that value? For instance, in the above example, I'd expect to have something like:

h = {
  :foo => <C @dict={:bar => 1}>,
  :baz => 10,
  :quux => <C @dict={:swozz => <C @dict={:muux => 1000}>, :grimel => 200}>
  # ...
}

where <C @dict = ...> represents a C instance with @dict = .... (Note that as soon as you reach a value which isn't nested, you stop wrapping it in C instances.)

解决方案

def convert_hash(h)
  h.keys.each do |k|
    if h[k].is_a? Hash
      c = C.new
      c.dict = convert_hash(h[k])
      h[k] = c
    end
  end
  h
end

If we override inspect in C to give a more friendly output like so:

def inspect
  "<C @dict=#{dict.inspect}>"
end

and then run with your example h this gives:

puts convert_hash(h).inspect

{:baz=>10, :quux=><C @dict={:grimel=>200,
 :swozz=><C @dict={:muux=>1000}>}>, :foo=><C @dict={:bar=>1}>}

Also, if you add an initialize method to C for setting dict:

def initialize(d=nil)
  self.dict = d
end

then you can reduce the 3 lines in the middle of convert_hash to just h[k] = C.new(convert_hash_h[k])

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