仅用php preg_replace替换字符串一次

问题描述

我需要一次替换字符串功能，并相信preg_match可能是我最好的选择.

I need a replace string once function and believe preg_match might be my best bet.

我正在使用此功能，但是由于使用的动态性，有时此功能的行为会很奇怪:

I was using this, but due to the dynamicness of use, sometimes this function behaves strangely:

function str_replace_once($remove , $replace , $string)
{
    $pos = strpos($string, $remove);
    if ($pos === false)
    {
    // Nothing found
    return $string;
    }
    return substr_replace($string, $replace, $pos, strlen($remove));
}

现在我正在采用这种方法，但是遇到了下面列出的错误....我正在使用此函数解析各种html字符串，因此很难给出导致错误的值.到目前为止，我对以下内容的使用中有80％显示此错误.

Now I am taking this approach but have ran to to the error listed below.... I'm parsing all kinds of html strings with this function, so its hard to give a value thats causing the error. As of now 80% of my uses of the below show this error .

function str_replace_once($remove , $replace , $string)
{
    $remove = str_replace('/','\/',$remove);
    $return = preg_replace("/$remove/", $replace, $string, 1);
    return $return;
}

错误:

任何人都可以完善解决方案吗?

Can anyone refine a solution?

推荐答案

您正在寻找preg_quote，而不是试图自己逃避\(不需要[，+等许多其他内容)考虑在内)

You are looking for preg_quote instead of trying to escape the \ yourself (which doesn't take [, + and many others into account):

$return = preg_replace('/'.preg_quote($remove,'/').'/', $replace, $string, 1);

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