使用正则表达式从文本文件中提取的字符串总和

问题描述

我刚刚学习 Python，需要一些帮助来完成我的课堂作业.

I am just learning python and need some help for my class assignment.

我有一个包含文本和数字的文件.有些行有 1 到 3 个数字，有些则根本没有数字.

I have a file with text and numbers in it. Some lines have from one to three numbers and others have no numbers at all.

我需要:

1. 使用正则表达式仅从文件中提取数字

1. Extract numbers only from the file using regex

求所有数之和

我使用正则表达式来提取所有数字.我试图得到所有数字的总和，但我只是得到每行有数字的总和.我一直在用不同的方法来完成这项任务，这是我最接近正确的方法.

I used regex to extract out all the numbers. I am trying to get the total sum of all the numbers but I am just getting the sum of each line that had numbers. I have been battling with different ways to do this assignment and this is the closest I have gotten to getting it right.

我知道我遗漏了一些关键部分，但我不确定我做错了什么.

I know I am missing some key parts but I am not sure what I am doing wrong.

这是我的代码:

import re
text = open('text_numbers.txt')

for line in text:
    line = line.strip()
    y = re.findall('([0-9]+)',line)

    if len(y) > 0:
        print sum(map(int, y))

我得到的结果是这样的(每个都是一行的总和):

The result I get is something like this(each is a sum of a line):

14151

8107

16997

18305

3866

它必须是这样的一个总和(所有数字的总和):

And it needs to be one sum like this (sum of all numbers):

134058

推荐答案

import re
import np
text = open('text_numbers.txt')
final = []
for line in text:
    line = line.strip()
    y = re.findall('([0-9]+)',line)

    if len(y) > 0:
         lineVal = sum(map(int, y))
         final.append(lineVal)
         print "line sum = {0}".format(lineVal)
 print "Final sum = {0}".format(np.sum(final))

这就是你要找的吗?

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