Julia中最小值的位置

问题描述

Julia 是否有内置命令来查找向量最小值的索引?例如，R 有一个 which.min 命令(当然还有一个 which.max).

Does Julia have a build in command to find the index of the minimum of a vector? R, for example, has a which.min command (and a which.max, of course).

显然，我可以自己编写以下内容，但最好不必这样做.

Obviously, I could write the following myself, but it would be nice not to have to.

function whichmin( x::Vector )
  i = 1
  min_x=minimum(x)
  while( x[i] > min_x )
    i+=1
  end
  return i
end

抱歉，如果以前有人问过这个问题，但我找不到.谢谢！

Apologies if this has been asked before, but I couldn't find it. Thanks!

推荐答案

从 0.7-alpha 开始，indmin 和 indmax 已被弃用.使用 argmin和 argmax而是.

Since 0.7-alpha, indmin and indmax are deprecated.Use argmin and argmax instead.

对于向量，它只返回线性索引

For a vector it just returns the linear index

julia> x = rand(1:9, 4)
4-element Array{Int64,1}:
 9
 5
 8
 5

julia> argmin(x)
2

julia> argmax(x)
1

如果同时查找索引和值，请使用 findmin 和 findmax.

If looking for both the index and the value, use findmin and findmax.

对于多维数组，所有这些函数都返回笛卡尔索引.

For multidimensional array, all these functions return the CartesianIndex.

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