正则表达式没有获得特殊字符的完整链接

问题描述

我正在使用此代码：

$string = preg_replace("~(?!(?:https?://(?:www\.)?|www\.)(?:youtube\.com)(?:https?://(?:www\.)?|www\.)[\w./=?#-]+~i", '<a href="$0">$0</a>', $string);

这样我就可以将下面的链接变成可点击的链接。

So that I can turn the link beneath into a clickable link.

http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin,%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg

这适用于某个部分......它建立了的链接http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton 但其余部分保留纯文本。如何使其适用于整个链接？所以你也看到逗号 ...我怎么能把它作为一个链接吗？

This works for a part... It makes a link of http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton but the rest stays plain text. How can I make it work for the whole link? So you see a comma too... How can I make that a link?

推荐答案

我也试图在URL的末尾说明标点符号（这样我们就不要不包括它。）

Also I'm trying to account for punctuation at the end of a URL (so that we don't include it).

<?php

$string = "This works http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg. This one should fail http://www.youtube.com/v/adlskdfjasopie. Although this one should fail as well http://youtu.be/adlkajdaslk.";

$string = preg_replace("~(?!(?:https?://(?:www\.)?|www\.)(?:youtu))(?:https?://(?:www\.)?|www\.)[^\s]+[^.!?,\<\]\[\)(]~i",'<a href="$0">$0</a>',$string);


?>

输出

This works <a href="http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg. ">http://upload.wikimedia.org/wikipedia/commons/f/f2/Bill_Clinton%2C_Yitzhak_Rabin%2C_Yasser_Arafat_at_the_White_House_1993-09-13.jpg. </a>This one should fail http://www.youtube.com/v/adlskdfjasopie. Although this one should fail as well http://youtu.be/adlkajdaslk.

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