问题描述
我需要构建一个路由器,将REST请求路由到正确的控制器和操作。这里有一些例子:
I need to build a router, that routes a REST request to a correct controller and action. Here some examples:
POST /users
GET /users/:uid
GET /users/search&q=lol
GET /users
GET /users/:uid/pictures
GET /users/:uid/pictures/:pid
重要的是要有一个正则表达式并且尽可能好,因为路由是必不可少的,并且在每次请求时都会完成。
It is important to have a single regular expression and as good as possible since routing is essential and done at every request.
我们首先必须用正则表达式替换:(直到结束或直到下一个正斜杠/),然后我们可以使用它来验证带有请求网址的网址。
we first have to replace : (untill end or untill next forward slash /) in the urls with a regex, that we can afterwards use to validate the url with the request url.
我们如何用正则表达式替换这些动态路由?就像搜索以:开头并以/结尾的字符串,字符串结尾或&。
How can we replace these dynamic routings with regex? Like search for a string that starts with ":" and end with "/", end of string or "&".
这是我试过的:
var fixedUrl = new RegExp(url.replace(/\\\:[a-zA-Z0-9\_\-]+/g, '([a-zA-Z0-0\-\_]+)'));
由于某种原因,它不起作用。我如何实现用正则表达式替换:id的正则表达式,或者在与真实请求网址进行比较时忽略它们。
For some reason it does not work. How could I implement a regex that replaces :id with a regex, or just ignores them when comparing to the real request url.
感谢您的帮助
推荐答案
我使用:[^ \s /] +
来匹配参数,以...开头冒号(匹配:
,然后尽可能多的字符,除了 /
和空格)。
I'd use :[^\s/]+
for matching parameters starting with colon (match :
, then as many characters as possible except /
and whitespace).
作为替换,我使用([\\\\ - ] +)
来匹配任何字母数字字符, - 和 _
。
As replacement, I'm using ([\\w-]+)
to match any alphanumeric character, -
and _
, in a capture group, given you're interested in using the matched parameters as well.
var route = "/users/:uid/pictures";
var routeMatcher = new RegExp(route.replace(/:[^\s/]+/g, '([\\w-]+)'));
var url = "/users/1024/pictures";
console.log(url.match(routeMatcher))
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