Python重新-在正则表达式模式中转义巧合括号

问题描述

我在以下代码中遇到了正则表达式问题:

I am having trouble with the regex in the following code:

import mechanize
import re

br = mechanize.Browser()
br.set_handle_robots(False)
br.addheaders = [('User-agent', 'Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.1) Gecko/2008071615 Fedora/3.0.1-1.fc9 Firefox/3.0.1')]
response = br.open("http://www.gfsc.gg/The-Commission/Pages/Regulated-Entities.aspx?auto_click=1")

html = response.read()
br.select_form(nr=0)
#print br.form
br.set_all_readonly(False)
next = re.search(r"""<a href="javascript:__doPostBack('(.*?)','(.*?)')">""",html)

if next:
    print 'group(1):', next.group(1)
    print 'group(2):', next.group(2)

如果将两个(.*?)实例的单引号从正则表达式中删除，则结果如下:

If the single quotes around both instances of (.*?) are removed from the regex, these are the results:

group(1): ('ctl00$ctl20$g_af5ce308_e786_4734_ad4c_9829087cffbd$ctl00$gvWebLicensee','Page$2')
group(2): ('ctl00$ctl20$g_af5ce308_e786_4734_ad4c_9829087cffbd$ctl00$gvWebLicensee'

这些结果不太正确.括号和单引号需要删除(不是我的问题)，我希望group(1)和group(2)看起来像这样:

These results are not quite right. The parentheses and single quotes need to be removed (not my question) and I would like group(1) and group(2) to look like this:

group(1): ctl00$ctl20$g_af5ce308_e786_4734_ad4c_9829087cffbd$ctl00$gvWebLicensee
group(2): Page$2

推荐答案

您需要转义括号，因为它们具有特殊含义:

You need to escape the parenthesis since they have a special meaning:

<a href="javascript:__doPostBack\('(.*?)','(.*?)'\)">
                             HERE^            HERE^

请注意，理想情况下，您不应使用正则表达式解析HTML(即使您的模式非常具体，我也不认为这是).而是使用 BeautifulSoup 解析HTML，找到a元素，获取href属性值，然后使用正则表达式提取所需的子字符串.

Note that, ideally, you should not be parsing HTML with regex (even though your pattern is quite specific and I don't think this is that bad). Instead, parse HTML with, say, BeautifulSoup, locate the a element, get the href attribute value and then extract the desired substrings with regex.

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