本文介绍了Java-提取方括号内的内容(忽略嵌套方括号)?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想提取方括号内的字符串内容(如果一个方括号内包含嵌套的方括号,应将其忽略).
I want to extract the string content inside square brackets (if inside one square brackets contains nested square brackets, it should be ignored).
示例:
c[ts[0],99:99,99:99] + 5 - d[ts[1],99:99,99:99, ts[2]] + 5
应返回:
match1 = "ts[0],99:99,99:99";
match2 = "ts[1],99:99,99:99, ts[2]";
到目前为止,我的代码仅适用于非嵌套方括号
The code I have so far works only with non-nested square brackets
String in = "c[ts[0],99:99,99:99] + 5 - d[ts[1],99:99,99:99, ts[2]] + 5";
Pattern p = Pattern.compile("\\[(.*?)\\]");
Matcher m = p.matcher(in);
while(m.find()) {
System.out.println(m.group(1));
}
// print: ts[0, ts[1, 2
推荐答案
不带正则表达式;只是笔直的Java:
Without regex; just straight java:
import java.util.ArrayList;
import java.util.List;
public class BracketParser {
public static List<String> parse(String target) throws Exception {
List<String> results = new ArrayList<>();
for (int idx = 0; idx < target.length(); idx++) {
if (target.charAt(idx) == '[') {
String result = readResult(target, idx + 1);
if (result == null) throw new Exception();
results.add(result);
idx += result.length() + 1;
}
}
return results;
}
private static String readResult(String target, int startIdx) {
int openBrackets = 0;
for (int idx = startIdx; idx < target.length(); idx++) {
char c = target.charAt(idx);
if (openBrackets == 0 && c == ']')
return target.substring(startIdx, idx);
if (c == '[') openBrackets++;
if (c == ']') openBrackets--;
}
return null;
}
public static void main(String[] args) throws Exception {
System.out.println(parse("c[ts[0],99:99,99:99] + 5 - d[ts[1],99:99,99:99, ts[2]] + 5"));
}
}
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