我怎么能自动删除的文件名的文件扩展名

问题描述

我试图让在bash脚本，需要从文件名中去除文件扩展名，如以下

 原文：something.zip
删除版本：什么
 

和我想我可以用削减这一点，但我担心的情况可能会出现在有可能是有一个以上的周期，等文件名，类似于以下的东西。

  something.v2.zip
 

话说回来，我想知道如果任何人有任何建议，以什么我所能做的只是删除最后一个周期，并从一行文本/文件名后面的文本？任何帮助将是AP preciated，谢谢！

解决方案

  F = file.zip
 回声$ {F％.zip文件} 文件
 

的'％'是一个参数调节剂，这意味着，从可变无论是％炭后的值的右侧删除，在这种情况下，串的.zip 。你可以让这个更一般的，以消除任何尾随的扩展，使用通配符像

 回声$ {F％。*} 文件
 

IHTH

I am trying to make a script in bash that requires the removal of the the file extension from a file name, like the following

original:   something.zip
removed version: something

And I was thinking I could use cut for this, but I am worried that a situation could arise where there might be a file name that has more than one period, etc, something similar to the following

something.v2.zip

having said that, I was wondering if anyone had any recommendations as to what I could do to just remove the last period and the text after it from a line of text/filename? any help would be appreciated, thanks!

解决方案

 f=file.zip
 echo ${f%.zip}

 file

The '%' is a parameter modifier, it means, delete from the right side of the value of the variable whatever is after the '%' char, in this case, the string .zip. You can make this more general to remove any trailing extension, by using a wild card like

 echo ${f%.*}

 file

IHTH

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