如何从preg_match输出中只删除真正的重复项？

问题描述

是的，我知道 array_unique 函数，但事实是该匹配在我的搜索字词中可能有合法的重复项，例如：

Yes I know array_unique function, but the thing is that match might have a legitimate duplicates in my search term for example:

$str = "fruit1: banana, fruit2: orange, fruit3: banana, fruit4: apple, fruit5: banana";
preg_match("@fruit1: (?<fruit1>\w+), fruit2: orange, fruit3: (banana), fruit4: (?<fruit4>apple), fruit5: (banana)@",$str,$match);
array_shift($match); // I dont need whole match
print_r($match);

输出是：

Array
(
    [fruit1] => banana
    [0] => banana
    [1] => banana
    [fruit4] => apple
    [2] => apple
    [3] => banana
)

所以真正重复的唯一键是[0]和[2]，但是 array_unique 给出：

So the only keys that are real duplicates are [0] and [2] but array_unique gives:

Array
(
    [fruit1] => banana
    [fruit4] => apple
)

推荐答案

我发现自己，解决方案是一段时间删除后续密钥的循环是不是数值的：

I found it myself, solution is a while loop that deletes subsequent key is one that it is at is not numerical:

while (next($match) !== false) {
  if (!is_int(key($match))) {
    next($match);
    unset($m[key($match)]);
  }
}
reset($match);

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