本文介绍了如何在同一模型的架构方法中创建模型实例?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
主题.我想在它的静态方法中初始化模型的新实例:
Subject. I want init a new instance of model in it static method:
var Schema = new mongoose.Schema({...});
//...
Schema.statics.createInstance = function (name, pass) {
var newPerson = new Person; // <--- or 'this', or 'Schema'?
newPerson.name = name;
newPerson.pass = pass;
newPerson.save();
return newPerson;
}
// ...
module.exports = db.model("Person", Schema);
我该怎么做?
推荐答案
您在正确的轨道上; this
是架构在schema.statics
方法中注册的模型,因此您的代码应更改为:
You were on the right track; this
is the Model the schema is registered as within a schema.statics
method, so your code should change to:
Schema.statics.createInstance = function (name, pass) {
var newPerson = new this();
newPerson.name = name;
newPerson.pass = pass;
newPerson.save();
return newPerson;
}
列昂尼德(Leonid)关于处理save
回调是正确的,即使只是记录错误也是如此.
And Leonid is right about handling the save
callback, even if it's only to log errors.
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