问题描述
我有一个JSON对象,并将其转换为Buffer
并在此处进行一些处理.稍后,我想转换相同的缓冲区数据以转换为有效的JSON对象.
I have a JSON object and I'm converting it to a Buffer
and doing some process here. Later I want to convert the same buffer data to convert to valid JSON object.
我正在研究Node V6.9.1
I'm working on Node V6.9.1
下面是我尝试的代码,但是当我转换回JSON并且无法打开此对象时,我得到了[object object]
.
Below is the code I tried but I'm getting [object object]
when I convert back to JSON and cannot open this object.
var obj = {
key:'value',
key:'value',
key:'value',
key:'value',
key:'value'
}
var buf = new Buffer.from(obj.toString());
console.log('Real Buffer ' + buf); //This prints --> Real Buffer <Buffer 5b 6f 62 6a 65 63 74>
var temp = buf.toString();
console.log('Buffer to String ' + buf); //This prints --> Buffer to String [object Object]
所以我尝试使用检查方式打印整个对象
So I tried to print whole object using inspect way
console.log('Full temp ' + require('util').inspect(buf, { depth: null })); //This prints --> '[object object]' [not printing the obj like declared above]
如果我尝试像数组一样读取它
If i try to read it like an array
console.log(buf[0]); // This prints --> [
我也尝试解析它引发SyntaxError: Unexpected token o in JSON at position 2
我需要像创建一样将其视为真实对象(我的意思是像上面声明的那样).
I need to view it as real object like I created (I mean like declared above).
请帮助.
推荐答案
您需要对json进行字符串化处理,而不要调用toString
You need to stringify the json, not calling toString
var buf = Buffer.from(JSON.stringify(obj));
用于将字符串转换为json obj
And for converting string to json obj :
var temp = JSON.parse(buf.toString());
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