问题描述
我刚刚阅读了加速的C ++(似乎是一本很棒的书)，最后作者说
I've just read the first chapter of Accelerated C++ (seems like an awesome book), and at the end the author says
为什么这被认为是好的做法?在C99中，我总是使用 exit()表示异常程序终止，而省略了 return 0 ，并且从未错过显式返回.
Why is this considered good practice? In C99, I always omitted the return 0, using exit() to signal abnormal program termination, and never missed the explicit return.
推荐答案
在C99和C ++中，如果程序的执行到达 main()函数的右括号，则隐式返回0; 被执行.在C90中不是这种情况-在没有明确的 return 的情况下到达 main()的末尾将导致返回不确定的值(严格来说，行为是不确定的)).
In C99 and in C++ if execution of the program reaches the closing brace of the main() function then an implicit return 0; is executed. That wasn't the case in C90 - reaching the end of main() without an explicit return would result in an indeterminate value being returned (strictly speaking, the behavior is undefined).
我只能猜测，"Accelerated C ++"的作者认为显式返回是一种好习惯，仅仅是因为它使您的意图变得显式.我能想到的唯一另一个原因是它使代码与C90兼容，但是我很难相信这会成为一个重要问题.
I can only guess that the authors of "Accelerated C++" feel that the explicit return is good practice simply because it makes your intent explicit. The only other reason I can think of is that it makes code compatible with C90, but I find it difficult to believe that that would hold much weight as a reason.
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