问题描述
编辑:我找到了从Core Data实体生成Swift模型的解决方案:
Edit: I found the solution to generate a Swift model from Core Data entity:
在Xcode上:
编辑器>创建NSManagedOjbect>点击按钮下一步>点击按钮下一步>选择SwiftLangage>点击按钮创建
Editor > Create NSManagedOjbect > Click button "Next" > Click button "Next" > Select "Swift" Langage > Click button "Create"
我通过使用Core Data在Xcode 6 beta上创建一个新的Swift项目来尝试Swift语言。
I tried Swift langage by creating a new Swift project on Xcode 6 beta using Core Data.
当我从Core Data的实体生成模型时,Xcode创建了Objective-C模型。
When I generate my models from my Core Data's entities, Xcode creates Objective-C models.
有没有办法生成Swift模型而不是Obejctive-C模型与核心数据?
Is there a way to generate Swift model rather than Obejctive-C model with Core Data ?
谢谢!
推荐答案
对Objective-C方式:
Lets have a look on the Objective-C way:
Person.h (Header-File)
Person.h (Header-File)
#import <Foundation/Foundation.h>
#import <CoreData/CoreData.h>
@interface Person : NSManagedObject
@property (nonatomic, retain) NSString *name;
@end
Person.m
#import "Person.h"
@implementation Person
@dynamic name;
@end
Swift
Xcode6-Beta中已经包含的文档说:
Swift
The documentation already included in Xcode6-Beta says:
这就是我将重写上述Swift(未测试)示例:
So that is how I would rewrite the above example for Swift (not tested):
Person.swift
import CoreData
class Person: NSManagedObject {
@NSManaged var name : NSString
}
根据你的问题,我认为子类生成功能可能不包括在Xcode6中。当你在Xcode中创建Cocoa-Project时,你确定你选择了Swift作为编程语言吗?
And according to your question I think the subclass-generation-feature might be not included in Xcode6 yet. Did you made sure that you have chosen "Swift" as programming language when you were creating the Cocoa-Project in Xcode?
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