本文介绍了如何序列化列表< customobject>用gson?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

大家好,

我有一个员工类:



 import java.util.List; 
公共类员工{
private String name;
私人弦乐专业;
private Integer profId;
private List< String>角色;

public String getName(){
return name;
}

public void setName(String name){
this.name = name;
}

public String getProfession(){
return profession;
}

public void setProfession(String profession){
this.profession = profession;
}

public Integer getProfId(){
return profId;
}

public void setProfId(Integer profId){
this.profId = profId;
}

public List< String> getRoles(){
返回角色;
}

public void setRoles(List< String> roles){
this.roles = roles;
}

@Override
public String toString(){
String result = name +\ n+ profession +\ n
+ profId +\ n+ roles.toString();

返回结果;
}

}





我尝试为员工列表生成Json表示:



列表<员工> emps = new ArrayList<>(); 
员工emp1 =新员工(){
{
setName(Hassan);
setProfession(医生);
setProfId(52);
setRoles(Arrays.asList(surgeon,nose));
}};

员工emp2 =新员工(){
{
setName(Jack);
setProfession(Developer);
setProfId(52);
setRoles(Arrays.asList(Java));
}};

员工emp3 =新员工(){
{
setName(Safy);
setProfession(Driver);
setProfId(52);
setRoles(Arrays.asList(Nice,Kind));
}};

emps.add(emp1);
emps.add(emp2);
emps.add(emp3);
Gson gson = new Gson();
类型type = new TypeToken< List< Employee>>(){}。getType();
String jsonString = gson.toJson(emps,type);







生成的jsonString =[null,null,null]



在调试emps List中有3名员工按预期进行,且没有一个是空的



怎样才能正常完成?



非常感谢!



我尝试了什么:



我搜索了,

所有答案都说我应该使用TypeToken声明我做的类型但没有结果,

解决方案

Hello every one,
I have an Employee class :

import java.util.List;
public class Employee {
    private String name;
    private String profession;
    private Integer profId;
    private List<String> roles;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getProfession() {
        return profession;
    }

    public void setProfession(String profession) {
        this.profession = profession;
    }

    public Integer getProfId() {
        return profId;
    }

    public void setProfId(Integer profId) {
        this.profId = profId;
    }

    public List<String> getRoles() {
        return roles;
    }

    public void setRoles(List<String> roles) {
        this.roles = roles;
    }

    @Override
    public String toString() {
        String result = name + "\n" + profession + "\n"
                + profId + "\n" + roles.toString();

        return result;
    }

}



I try to generate a Json representation for a list of employees :

List<Employee> emps = new ArrayList<>();
Employee emp1 = new Employee(){
            {
                setName("Hassan");
                setProfession("doctor");
                setProfId(52);
                setRoles( Arrays.asList("surgeon" ,  "nose"));
            }};

        Employee emp2 = new Employee(){
            {
                setName("Jack");
                setProfession("Developer");
                setProfId(52);
                setRoles( Arrays.asList("Java" ));
            }};

        Employee emp3 = new Employee(){
            {
                setName("Safy");
                setProfession("Driver");
                setProfId(52);
                setRoles( Arrays.asList("Nice" , "Kind" ));
            }};

        emps.add(emp1);
        emps.add(emp2);
        emps.add(emp3);
Gson gson = new Gson();
Type type = new TypeToken<List<Employee>>(){}.getType();
String jsonString = gson.toJson(emps,type);




The resulting jsonString = "[null,null,null]"

in debug the emps List has the 3 employees as expected and none of them is null

How can this be properly done ?

Thanks very much!

What I have tried:

I searched,
all the answers said I should just use the TypeToken in declaring the type witch I did but with no result,

解决方案


这篇关于如何序列化列表&lt; customobject&gt;用gson?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-14 12:32