本文介绍了为什么我使用 = (单个等于)的相等比较在 Java 中不能正常工作?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在以下行中出现语法错误.但是我不明白这个错误的原因是什么.

I have a syntax error in the following line. However I can't understand what is the reason of this error.

if (address1.compareTo(address2) = 1)
        System.out.println(address1 + " is greater than " + address2);

我想要实现的是当且仅当 compareTo 返回 1 时打印正确的消息.

What I want to achieve is printing proper message if and only if compareTo returns 1.

推荐答案

您应该比较 (==) 而不是分配 (=).这可能非常危险!为了避免这种情况,您可以使用 Yoda 符号 代替比较

You should compare (==) instead of assigning (=). It can be very dangerous! To avoid such situations you can use Yoda notation so instead of comparing

address1.compareTo(address2) == 1

你可以比较:

1 == address1.compareTo(address2)

如果缺少=,会出现比较错误.

In case of missing =, there will be comparation error.

在您的情况下,最好进行比较:

In your case, it would be better to compare:

address1.compareTo(address2) > 0

这篇关于为什么我使用 = (单个等于)的相等比较在 Java 中不能正常工作?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-14 11:32