本文介绍了如何使用unordered_set?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想这样定义一个unordered_set:

I am trying to define an unordered_set like this:

unordered_set<Point> m_Points;

当我编译它,我得到以下错误:

When I compile it, I get the following error:

code> Point :

Class Point:

class Point{
    private:
        int x, y;
    public:
        Point(int a_x, int a_y)
            : x(a_x), y(a_y)
        {}
        ~Point(){}

        int getX()const { return x; }
        int getY()const { return y; }

        bool operator == (const Point& rhs) const{
            return x == rhs.x && y == rhs.y;
        }

        bool operator != (const Point& rhs) const{
            return !(*this == rhs);
        }
};




  • 如何/在何处为点定义散列函数

  • 对于2D点,什么是好的哈希函数?

  • 推荐答案

    std :: unordered_set 需要您写来存储和查找自己的类型。

    std::unordered_set requires you to write hash functions to store and find your own types.

    基本类型和许多类型在 std 命名空间在 std :: hash< Key> 中有这样的散列函数。这些函数遵循:

    Base types and many types in the std namespace do have such hash functions within std::hash<Key>. These functions follow certain rules:


    1. 接受的单个参数。

    在调用时不会抛出异常

    对于两个参数 k1 k2 等于 std :: hash< Key>()(k1)== std :: hash< Key>()(k2)

    对于两个不同的参数 k1 k2 ,则 std :: hash< Key>()(k1)== std :: hash< Key>()(k2)的概率应该非常小, code> 1.0 / std :: numeric_limits< size_t> :: max()。

    For two different parameters k1 and k2 that are not equal, the probability that std::hash<Key>()(k1) == std::hash<Key>()(k2) should be very small, approaching 1.0/std::numeric_limits<size_t>::max().


    $ b b

    现在我们得到了定义,让我们考虑一下什么是你的点结构的好的哈希函数。有 std :: pair (非常类似于点结构)有一个散列函数,但不幸的是,没有使它成为C ++ 11标准。

    Now that we got the definitions out of the way, let's think about what would be a good hash function for your point structure. There was a request that std::pair (which is very similar to a point structure) got a hash function, but, unfortunately, that did not make it into the C++11 standard.

    但我们很幸运:SO是真棒,当然,你基本上可以。注意,你不必自己散列整数,因为 std :: hash 已经有一个专门化。因此,让我们深入一下哈希函数,根据:

    But we are lucky: SO is awesome and, of course, you can basically already find the answer. Note that you do not have to hash integers yourself, because std::hash has a specialization for that already. So let's dig into our hash function, according to this answer:

    namespace std
    {
        template <>
        struct hash<Point>
        {
            size_t operator()(Point const & x) const noexcept
            {
                return (
                    (51 + std::hash<int>()(x.getX())) * 51
                    + std::hash<int>()(x.getY())
                );
            }
        };
    }
    

    我们完成了。

    这篇关于如何使用unordered_set?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

08-14 10:34