问题描述
有一个简单的问题。我已经在互联网上四处浏览，找到了一些解决方案，但都没有一个有效的方法。在将字符串转换为int时，并不是指ASCII码。
Just have a quick question. I've looked around the internet quite a bit and I've found a few solutions but none of them have worked yet. Looking at converting a string to an int and I don't mean ASCII codes.
为了快速调试，我们将方程式作为字符串传递。我们将其分解，正确设置格式并求解线性方程。现在，我无法将字符串转换为int。
For a quick run-down, we are passed in an equation as a string. We are to break it down, format it correctly and solve the linear equations. Now, in saying that, I'm not able to convert a string to an int.
我知道字符串的格式为（-5）或（25）等，因此绝对是int。但是我们如何从字符串中提取出来呢？
I know that the string will be in either the format (-5) or (25) etc. so it's definitely an int. But how do we extract that from a string?
我想到的一种方式是在字符串中运行for / while循环，检查一个数字，提取所有数字之后，然后查看是否有前导-，如果有，则将int乘以-1。
One way I was thinking is running a for/while loop through the string, check for a digit, extract all the digits after that and then look to see if there was a leading '-', if there is, multiply the int by -1.
一个小问题。有想法吗？
It seems a bit over complicated for such a small problem though. Any ideas?
推荐答案
在C ++ 11中， std有一些不错的新转换函数：字符串转换为数字类型。
In C++11 there are some nice new convert functions from std::string to a number type.
因此代替
atoi( str.c_str() )
您可以使用
std::stoi( str )
其中 str 是您的数字，作为 std :: string 。
where str is your number as std::string.
有各种版本的数字：
长号stol（string）， float stof（string） ，双螺柱（字符串），...
参见
There are version for all flavours of numbers:long stol(string), float stof(string), double stod(string),...see http://en.cppreference.com/w/cpp/string/basic_string/stol
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