为嵌套的 NSDictionary 生成完整的键值编码路径列表?

问题描述

我有一个包含键和值的 NSDictionary，有些值也将是 NSDictionarys... 到任意(但合理)的级别.

我想获得所有有效 KVC 路径的列表，例如给定:

{"foo" = "bar",qux"= {炸玉米饼"=美味"，"burrito" = "也很好吃",}}

我会得到:

["富","qux","qux.taco",qux.burrito"]

是否有一种已经存在的简单方法可以做到这一点?

解决方案

您可以通过 allKeys 递归.一个键显然是一个键路径，然后如果值是一个 NSDictionary 你可以递归和追加.

- (void)获取KeyPaths:(id)val intoArray:(NSMutableArray*)arr withString:(NSString*)s {如果 ([val isKindOfClass:[NSDictionary 类]]) {for (id aKey in [val allKeys]) {NSString* 路径 =(!s ? aKey : [NSString stringWithFormat:@"%@.%@", s, aKey]);[arr addObject: 路径];[自获取KeyPaths:[val objectForKey:aKey]进入数组: arrwithString: 路径];}}}

这里是如何调用它:

NSMutableArray* arr = [NSMutableArray 数组];[自获取KeyPaths:d intoArray:arr withString:nil];

之后，arr 包含您的关键路径列表.

I have an NSDictionary that contains keys and values, and some values will also be NSDictionarys... to an arbitrary (but reasonable) level.

I would like to get a list of all valid KVC paths, e.g. given:

{
    "foo" = "bar",
    "qux" = {
        "taco" = "delicious",
        "burrito" = "also delicious",
    }
}

I would get:

[
    "foo",
    "qux",
    "qux.taco",
    "qux.burrito"
]

Is there a simple way to do this that already exists?

解决方案

You could recurse through allKeys. A key is a key path, obviously, and then if the value is an NSDictionary you can recurse and append.

- (void) obtainKeyPaths:(id)val intoArray:(NSMutableArray*)arr withString:(NSString*)s {
    if ([val isKindOfClass:[NSDictionary class]]) {
        for (id aKey in [val allKeys]) {
            NSString* path =
                (!s ? aKey : [NSString stringWithFormat:@"%@.%@", s, aKey]);
            [arr addObject: path];
            [self obtainKeyPaths: [val objectForKey:aKey]
                       intoArray: arr
                      withString: path];
        }
    }
}

And here is how to call it:

NSMutableArray* arr = [NSMutableArray array];
[self obtainKeyPaths:d intoArray:arr withString:nil];

Afterwards, arr contains your list of key paths.

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