根据超类中的NSInteger属性使用NSPredicate过滤对象数组 | 根据超类中的NSInteger属性使用NSPredicate过滤

本文介绍了根据超类中的NSInteger属性使用NSPredicate过滤对象数组的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有以下设置:

@interface Item : NSObject {
    NSInteger *item_id;
    NSString *title;
    UIImage *item_icon;
}

@property (nonatomic, copy) NSString *title;
@property (nonatomic, assign) NSInteger *item_id;
@property (nonatomic, strong) UIImage *item_icon;

- (NSString *)path;

- (id)initWithDictionary:(NSDictionary *)dictionairy;

@end

还有

#import <Foundation/Foundation.h>
#import "Item.h"

@interface Category : Item {

}

- (NSString *)path;

@end

我有一个包含Category实例(称为"categories")的数组，我想根据它的item_id取出一个项目.这是我使用的代码:

I've got an array with Category instances (called 'categories') that I'd like to take a single item out based on it's item_id. Here is the code I use for that:

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"item_id == %d", 1];
NSArray *filteredArray = [categories filteredArrayUsingPredicate:predicate];

这会导致以下错误:

如何解决此问题，我在做什么错?属性已综合，我可以访问并成功在Category实例上设置item_id属性.

How can I fix this and what am I doing wrong? the properties are synthesized and I can acces and set the item_id property successfully on Category instances.

推荐答案

您已将item_id属性声明为指针.但是NSInteger是标量类型(32位或64位整数)，因此应将其声明为

You have declared the item_id property as a pointer. But NSInteger is a scalar type (32-bit or 64-bit integer), so you should declare it as

@property (nonatomic, assign) NSInteger item_id;

备注:从LLVM 4.0编译器(Xcode 4.4)开始，@synthesize和实例变量都会自动生成.

Remark: Starting with the LLVM 4.0 compiler (Xcode 4.4), both @synthesize and the instance variables are generated automatically.

这篇关于根据超类中的NSInteger属性使用NSPredicate过滤对象数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！