如何连接code字符串在迅速采用base64

问题描述

我想一个字符串转换为一个base64。我发现同样的答案在几个地方，但它不能在迅速再工作。我用X code 6.2。我相信答案可能是previous X code工件不是X code 6.2。

I want to convert a string to a base64. I found same answer in several places but it does not work anymore in swift. I am using Xcode 6.2. I believe the answer might be work in previous Xcode not Xcode 6.2.

可能有人请引导我做这个以x code 6.2？

Could someone please guide me to do this in Xcode 6.2 ?

我找到了答案是这样的。但它并没有在X code工件6.2

The answer I found was this. but it does not work in Xcode 6.2

var str = "iOS Developer Tips encoded in Base64"
println("Original: \(str)")

// UTF 8 str from original
// NSData! type returned (optional)
let utf8str = str.dataUsingEncoding(NSUTF8StringEncoding)

// Base64 encode UTF 8 string
// fromRaw(0) is equivalent to objc 'base64EncodedStringWithOptions:0'
// Notice the unwrapping given the NSData! optional
// NSString! returned (optional)
let base64Encoded = utf8str.base64EncodedStringWithOptions(NSDataBase64EncodingOptions.fromRaw(0)!)
println("Encoded:  \(base64Encoded)")

// Base64 Decode (go back the other way)
// Notice the unwrapping given the NSString! optional
// NSData returned
let data = NSData(base64EncodedString: base64Encoded, options:   NSDataBase64DecodingOptions.fromRaw(0)!)

// Convert back to a string
let base64Decoded = NSString(data: data, encoding: NSUTF8StringEncoding)
println("Decoded:  \(base64Decoded)")

REF：<一href=\"http://iosdevelopertips.com/swift-$c$c/base64-en$c$c-de$c$c-swift.html\">http://iosdevelopertips.com/swift-$c$c/base64-en$c$c-de$c$c-swift.html

推荐答案

我没有安装6.2，但我不认为是6.3在这方面有什么不同：

I don’t have 6.2 installed but I don’t think 6.3 is any different in this regard:

dataUsingEncoding 返回一个可选的，所以你需要解开了。

dataUsingEncoding returns an optional, so you need to unwrap that.

NSDataBase64EncodingOptions.fromRaw 已被替换 NSDataBase64EncodingOptions（rawValue：）。稍微出人意料的是，这不是一个failable初始化，所以你并不需要解开它。

NSDataBase64EncodingOptions.fromRaw has been replaced with NSDataBase64EncodingOptions(rawValue:). Slightly surprisingly, this is not a failable initializer so you don’t need to unwrap it.

不过，由于的NSData（base64En codedString：）的是的一个failable初始化，需要解开了

But since NSData(base64EncodedString:) is a failable initializer, you need to unwrap that.

顺便说一句，所有这些变化进行了X code迁移建议（请在阴沟里的错误信息，它有一个修复的建议）。

Btw, all these changes were suggested by Xcode migrator (click the error message in the gutter and it has a "fix-it" suggestion).

最后code，改写避免力解包，看起来是这样的：

Final code, rewritten to avoid force-unwraps, looks like this:

import Foundation

let str = "iOS Developer Tips encoded in Base64"
println("Original: \(str)")

let utf8str = str.dataUsingEncoding(NSUTF8StringEncoding)

if let base64Encoded = utf8str?.base64EncodedStringWithOptions(NSDataBase64EncodingOptions(rawValue: 0))
{

    println("Encoded:  \(base64Encoded)")

    if let base64Decoded = NSData(base64EncodedString: base64Encoded, options:   NSDataBase64DecodingOptions(rawValue: 0))
                          .map({ NSString(data: $0, encoding: NSUTF8StringEncoding) })
    {
        // Convert back to a string
        println("Decoded:  \(base64Decoded)")
    }
}

（如果使用雨燕1.2，您可以使用多个if-可以代​​替图）

(if using Swift 1.2 you could use multiple if-lets instead of the map)

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