在gdb中显示取消引用的STL迭代器

问题描述

我有一个迭代器到map元素，我想gdb显示迭代器的第一和第二元素的值。
例如：

I have an iterator to a map element, and I would like gdb to show me the values of the "first" and "second" elements of that iterator.For example:

std::map<int,double> aMap;
...fill map...
std::map<int,double>::const_iterator p = aMap.begin();

我可以在代码中使用p.first和p.second， gdb。对于什么是值得的，在dbx中可以做一些像print p.node.second_，但是我可以在gbd中找到类似的东西。

I can use p.first and p.second in the code, but can't see them in gdb. For what it's worth, in dbx one could do something like "print p.node.second_", but I can find anything similar in gbd.

我完全愿意有一个函数，我传递的对象类型，但我已经无法让它工作。

I am totally willing to have a function into which I pass the object types, but I've been unable to get that to work either.

任何想法？
谢谢！

Any ideas?Thanks!

推荐答案

这是我怎么做：

This GDB was configured as "i686-pc-linux-gnu"...
(gdb) list
1       #include <iostream>
2       #include <map>
3
4       int main()
5       {
6           std::map<int, int> a;
7           a[10] = 9;
8           std::map<int, int>::iterator it = a.begin();
9           ++it;
10      }
(gdb) b test.cpp:9
Breakpoint 1 at 0x8048942: file test.cpp, line 9.
(gdb) r
Starting program: /home/js/cpp/a.out

Breakpoint 1, main () at test.cpp:9
9           ++it;
(gdb) set print pretty on
(gdb) p it
$1 = {
  _M_node = 0x94fa008
}
(gdb) p *it
$2 = (class std::pair<const int, int> &) @0x94fa018: {
  first = 10,
  second = 9
}
(gdb)

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