问题描述
我想切换float和double值的字节序"，通过执行以下操作可以正常工作:
I'd like to switch the "endianness" of float and double values, it works OK, by doing something like:
float const v{1.f};
swap(reinterpret_cast<::std::uint32_t const&>(v));
在没有强制转换的情况下，是否存在更好的交换方法?
Does there exist a better way to do the swap, without a cast?
swap()是gcc内置函数的C ++包装器，在此未提供.
swap() is a C++ wrapper for gcc's built-in functions, I did not include it here.
uint16_t __builtin_bswap16 (uint16_t x)
uint32_t __builtin_bswap32 (uint32_t x)
uint64_t __builtin_bswap64 (uint64_t x)
对于某些数据格式(例如CBOR)，需要交换字节序.
Swapping of endianess is needed for a some data formats, like CBOR.
推荐答案
虽然尝试避免强制转换是一种很好的做法，但正是这种用法才是存在强制转换的原因.字节序交换是原始数据操作，因此要执行此操作，您必须除去键入信息，我想说的是，如果开头不是字节序正确，则它不是浮点数，因此永远不应以这种方式键入处于错误的状态状态.
While it is good practice to try and avoid casts, it's uses like this that are the reason casts exist. An endian swap is a raw data operation so in order to do it you must strip away the typing information, I would say that if it is not endian correct to begin with, then it is not a float and should never have been typed that way while in the wrong endianess state.
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