在dplyr group_by函数中出错，找不到对象

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问题描述

我提出这个问题，因为作为R的新人，我很好奇为什么我写的一段代码工作正常，然后在下一次运行时，同一行代码会产生错误。

以下是我正在使用的表格示例。

Dput：

  structure（list（a5species = structure（c（4L，1L，6L，3L，14L，3L，
 8L，8L，8L，8L，8L ，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，4L，8L， ，3L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L，8L， ，8L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，4L， ，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L，3L， ，
 3L，3L，1L，4L，3L，3L，3L，4L，3L，3L，3L，3L，4L，4L，4L，3L，
 4L，8L，4L，4L，4L ，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L， ，4L，4L，4L，4L， 
 4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，
 4L，4L，3L，12L，12L， 4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L， 4L，3L，
 12L，14L，6L，3L，3L，4L，4L，10L，4L，3L，3L，3L，3L，10L，4L，
 4L，4L，4L，12L， 4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L， 4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L， 4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L， 4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L，4L， 4L，
 4L，4L，4L，4L，6L，5L，4L，10L，12L，4L，4L，3L，6L，4L，3L，
 4L），.Label = c（coustani ，bbbbgarnhami，indetermine，marshallii，pharoensis，preoriensis，
rufipes，salbaii squamosus，tenebrosus，ziemani），class =factor），
 Vila = c（Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze，Motaze，Motaze ，
Motaze，Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze Motaze，Motaze，
Motaze，Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze，Motaze，Motaze，Motaze $ bMotaze，Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze，Motaze Motaze，
Motaze，Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze Motaze，Motaze，b，Motaze，Motaze，Motaze，Motaze，Motaze，Motaze ，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze，Motaze，Motaze，Motaze，
 Motaze，Motaze，Motaze，Motaze，Motaze，b，Motaze，Motaze，Motaze ，
Motaze，Motaze，Motaze，Motaze，Motaze，Motaze，
Motaze，Motaze，Motaze，Motaze Motaze，Motaze，
Motaze，Motaze，Motaze，Chicutso，Chicutso，Chicutso，
Chicutso，Chicutso ，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso， Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso， ，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso Chicutso，
Chicutso，Chicutso，Chicuts Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso ，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso，Chicutso， Chic ut，Chic ut ane，Chic ut ane，Pan ut，Chic ut， ，Panjane，Panjane，
Panjane，Panjane，Panjane，Panjane，Panjane，Magude，
Magude，Magude Magude，Magude，Magude，
Magude，Magude，Magude，Magude，Magude，Magude，
Magude ，Nug，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge， ，Muginge，
Muginge，Muginge，M Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge ，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge， ，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge，Muginge ，Muginge，Muginge，Nug，Muginge，Muginge，Muginge，B $ b，Muginge，Muginge Muginge，Muginge，Muginge，Mapulanguene，Mapulanguene，
Mapulanguene，Mapulanguene，Mapulanguene，Mapulanguene，
Mapulanguene ，Mapulangu ene，Mapulanguene，
Mapulanguene，Mapulanguene）），class = c（tbl_df，tbl，
data.frame），row.names = c NA，-321L），.Names = c（a5species，
Vila））

  test％>％+ group_by（Vila）％ >％filter（a5species ==gambiae）％>％+ summarize（n = n（））

使用此代码生成了我想要的表，但是下次尝试运行代码时，它停止工作并产生错误：

 code> group_by _（。data，.dots = lazyeval :: lazy_dots（...），add = add）中的错误：
对象'Vila'未找到

我知道这与发布在这里的问题类似：

但是我正在使用dplyr_0.4.3，而这个问题表明，他们遇到的问题现在已经修复了，而且我的代码也在一个工作。此外，关于这篇文章的讨论是相当技术性的，它超越了我的头脑。

任何想法为什么我的代码突然停止工作？

谢谢。

解决方案

当我们使用 + 标志。 + 表示代码未完成。我们可以手动删除 + 符号，或者将代码复制并粘贴到一个好的编辑器中以将其删除。

  test％>％
 group_by（Vila）％>％
过滤器（a5species ==gambiae）％>％
总结（n = n（））

 
 
  OP的代码
 
 
 
  test％>％+ group_by（Vila）％>％filter（a5species ==gambiae）％>％+总结（n = n（））
 ^^ ^^ 
  
 
 
 
 
I am asking this question because, as someone new to R, I am curious to why a piece of code I wrote works fine, and then the same line of code produces an error the next time it is run.
Here is an example of a table I am working with.
Dput: 
structure(list(a5species = structure(c(4L, 1L, 6L, 3L, 14L, 3L,
8L, 8L, 8L, 8L, 8L, 8L, 3L, 4L, 4L, 8L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 8L, 8L, 8L, 8L, 8L, 8L, 4L, 8L, 8L, 8L, 3L, 8L, 8L, 8L,
12L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L, 8L,
8L, 8L, 8L, 8L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 3L, 4L, 3L, 6L,
3L, 4L, 4L, 3L, 3L, 6L, 6L, 3L, 3L, 3L, 3L, 3L, 3L, 6L, 3L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 8L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L,
3L, 3L, 1L, 4L, 3L, 3L, 3L, 4L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 3L,
4L, 8L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 3L, 12L, 12L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 13L, 4L, 4L, 4L, 6L, 4L, 3L,
12L, 14L, 6L, 3L, 3L, 4L, 4L, 10L, 4L, 3L, 3L, 3L, 3L, 10L, 4L,
4L, 4L, 4L, 12L, 4L, 4L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 6L, 5L, 4L, 10L, 12L, 4L, 4L, 3L, 6L, 4L, 3L,
4L), .Label = c("coustani", "demeilloni", "funestus", "gambiae",
"garnhami", "indetermine", "marshallii", "pharoensis", "pretoriensis",
"rufipes", "salbaii", "squamosus", "tenebrosus", "ziemani"), class = "factor"),
    Vila = c("Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Motaze", "Motaze", "Motaze",
    "Motaze", "Motaze", "Motaze", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Chicutso", "Chicutso", "Chicutso",
    "Chicutso", "Chicutso", "Panjane", "Panjane", "Panjane",
    "Panjane", "Panjane", "Panjane", "Panjane", "Panjane", "Panjane",
    "Panjane", "Panjane", "Panjane", "Panjane", "Panjane", "Magude",
    "Magude", "Magude", "Magude", "Magude", "Magude", "Magude",
    "Magude", "Magude", "Magude", "Magude", "Magude", "Magude",
    "Magude", NA, NA, "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", NA, NA, "Muginge",
    "Muginge", "Muginge", "Muginge", "Muginge", "Muginge", "Muginge",
    "Muginge", "Muginge", "Muginge", "Mapulanguene", "Mapulanguene",
    "Mapulanguene", "Mapulanguene", "Mapulanguene", "Mapulanguene",
    "Mapulanguene", "Mapulanguene", "Mapulanguene", "Mapulanguene",
    "Mapulanguene", "Mapulanguene")), class = c("tbl_df", "tbl",
"data.frame"), row.names = c(NA, -321L), .Names = c("a5species",
"Vila"))
And I used this code to organise the species by Vila: 
test %>% + group_by(Vila) %>% filter(a5species=="gambiae") %>%  + summarise(n=n())
Using this code produced the table I want, but the next time I tried to run the code it stopped working and produces the error:
Error in group_by_(.data, .dots = lazyeval::lazy_dots(...), add = add) :
  object 'Vila' not found
I realise this is similar to the question posted here:R object not found if defined within a function when using data.table dplyr
But I am using dplyr_0.4.3 and this question suggests that the problem they were experiencing would have been fixed by now, and also my code did work at one point. Further more, the discussion on this post is quite technical and it goes over my head. 
Any idea why my code suddenly stopped working?
Thank you. 
 解决方案 
This occurred when we are copying the code from a R console with + sign.  The + signifies that the code is not complete. We can either remove the + sign manually or copy and paste the code in a good editor to remove those.
test %>%
    group_by(Vila) %>%
    filter(a5species=="gambiae") %>%
    summarise(n=n())
The OP's code
test %>% + group_by(Vila) %>% filter(a5species=="gambiae") %>%  + summarise(n=n())
         ^^                                                     ^^
                        
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