读取用户命令继续不起作用

问题描述

我写了计费系统的程序。我用我的程序do-whil​​e循环。和程序，根据用户的输入执行。如果用户要继续执行，程序将继续进行。但我得到了执行中的概率。我试图用简单的do-whil​​e循环我的逻辑。同样的问题也出现了简单的do-whil​​e循环也。

I'm Writing a program for Billing System. I'm using do-while loop in my program. And the program is executed according to user input. If the user want to continue the execution, the program will be continue. But I Got a prob in Execution. I was trying my logic in simple do-while loop. The same Problem arises for simple do-while loop also.

Problem is: If the input is yes, the program does not get the further input from user.

这是简单的do-whil​​e循环是：

That simple do-while loop is:

#include <stdio.h>

main()
{
    int c;
    char ch;
    do
    {
            printf("enter the no less then 4:");
            scanf("%d",&c);
        switch(c)
        {
            case 1:
                printf("In 1\n");
                break;
            case 2:
                printf("In 2\n");
                break;
            case 3:
                printf("In 3\n");
                break;
        }
        printf("do u want to continue?:");
        ch=getchar();
    }while(ch=='y');
}

如果我把而（CH！='N'）而不是，而（CH =='Y'）程序工作正常。我无法理解这背后的问题。请帮我纠正。并解释这个problem.Thankü提前。

If i put while(ch != 'n') instead of while(ch=='y') the program working fine. I couldn't understand the problem behind this. Please Help me to rectify this. And Explain about this problem.Thank u in advance.

推荐答案

第一次运行，3打印，用户键入Y和presses返回

first run, 3 is printed, user types "y" and presses return

的getchar（）读取'Y'和程序循环

getchar() reads 'y' and program loops

第二次的getchar（）从$ P $读取换行符pvious键preSS

second time, getchar() reads newline character from the previous key press

新行不是'Y'这样的程序不循环

newline is not 'y' so program does not loop

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