本文介绍了增强的“for"循环导致 ArrayIndexOutOfBoundsException的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
这是我的代码:
import java.util.Scanner;
public class Arrays {
public static void main(String[] args) {
Arrays psvm = new Arrays();
psvm.start();
}
public void start() {
Scanner ben = new Scanner(System.in);
int[] arr = new int[4];
int[] arrs = new int[4];
for (int i = 0; i < arr.length; i++) {
arr[i] = ben.nextInt();
}
check(arr, arrs);
}
public void check(int arr[], int arrs[]) {
for (int i = 0; i < arr.length; i++) {
arrs[i] = arr[i];
}
for (int i : arrs) {
System.out.println(arrs[i]);
}
}
}
增强的for
循环给出了ArrayIndexOutOfBoundsException
:
for (int i : arrs) {
System.out.println(arrs[i]);
}
虽然这个 for
循环语句有效.为什么?代码有什么问题?
While this for
loop statement works. Why? What's wrong with the code?
for (int i = 0; i < arrs.length; i++) {
System.out.println(arrs[i]);
}
推荐答案
在这种情况下,i
将分配给数组中的每个元素 - 它不是索引到数组中.
In this case, i
will be assigned to each element in the array - it is not an index into the array.
你想做的是:
for(int i : arrs)
{
System.out.println(i);
}
在您的代码中,您尝试选择迭代对象引用的数组索引处的整数.换句话说,你的代码相当于:
In your code, you're trying to select the integer at the array index referenced by the iteration object. In other words, your code is equivalent to:
for(int idx = 0; idx < arrs.length; idx++)
{
int i = arrs[idx];
System.out.println(arrs[i]);
}
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