将派生类根序列化为具有类型的基类名称

问题描述

我不知何故无法实现此序列化.我有这些课

I am somehow not able to achieve this serialization. I have these classes

public class Data
{
    [XmlElement("Name")]
    public string Name { get; set; }
}

[XmlRoot("Data")]
public class DataA : Data
{
    [XmlElement("ADesc")]
    public string ADesc { get; set; }
}

[XmlRoot("Data")]
public class DataB : Data
{
    [XmlElement("BDesc")]
    public string BDesc { get; set; }
}

当我序列化 DataA 或 DataB 时，我应该得到以下结构中的 XML:

When I serialize either DataA or DataB I should get the XMLs in the below structure:

<Data xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="" i:type="DataA">
      <Name>A1</Name>
      <ADesc>Description for A</ADesc>
</Data>

<Data xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="" i:type="DataB">
      <Name>B1</Name>
      <BDesc>Description for b</BDesc>
</Data>

我得到的是以下内容(没有 i:type="..." 和 xmlns="")

What I am getting is the below (without the i:type="..." and xmlns="")

<Data xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
      <Name>A1</Name>
      <ADesc>Description for A</ADesc>
</Data>

<Data xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
      <Name>B1</Name>
      <BDesc>Description for b</BDesc>
</Data>

我不确定我在这里遗漏了什么.任何建议都会有所帮助.

I am not sure what I am missing here. any suggestions would be helpful.

• 吉里哈

推荐答案

您应该包括基类的 XML 序列化的派生类型.

You should include the derived types for XML Serialization of the base class.

然后你可以为基类型创建一个序列化器，当你序列化任何派生类型时，它会添加类型属性:(你现在甚至可以从派生类中删除[Root] sttribute)

Then you can create a serializer for the base type, and when you serialize any derived type, it will add the type attribute: (You can even remove the [Root] sttribute from the derived classes now)

[XmlInclude(typeof(DataA))]
[XmlInclude(typeof(DataB))]
[XmlRoot("Data", Namespace = Data.XmlDefaultNameSpace)]
public class Data
{
    public const string XmlDefaultNameSpace = "http://www.stackoverflow.com/xsd/Data";

    [XmlElement("Name")]
    public string Name { get; set; }
}

序列化:

DataA a = new DataA() { ADesc = "ADesc", Name = "A" };
DataB b = new DataB() { BDesc = "BDesc", Name = "B" };
new XmlSerializer(typeof(Data)).Serialize(Console.OpenStandardOutput(), a);
new XmlSerializer(typeof(Data)).Serialize(Console.OpenStandardOutput(), b);

这是DataA类序列化的输出

Here is the output for DataA class serialization

<?xml version="1.0"?>
<Data xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xsi:type="DataA" xmlns="http://www.stackoverflow.com/xsd/Data">
  <Name>A</Name>
  <ADesc xmlns="">ADesc</ADesc>

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