枚举！

稍后在代码中，我有一个返回ADDR类型的函数， 返回一个指向正确值的整数但是我要打印 out名称一，二或三。 我怎么能这样做，我的例子有很多案例，所以不想使用 开关语句。 谢谢， Kapil 解决方案 "卡皮尔科斯拉 < KH ********* @ yahoo.com>在留言中写道 news：91 ************************** @ posting.google.c om ... 我有一个代码，其中我有一个枚举类似 枚举ADDR {一个= 0; two = 1; 三= 2; }; 后来在代码中，我有一个返回ADDR类型的函数，它返回一个整数指的是正确的价值，但我想打印出一两个或三个名字。我怎么能这样做，我的例子有很多案例所以不想使用切换声明。 AFAIK在你的情况下是不可实现的（带枚举）。 为什么不使用地图？ J.Schafer Kapil Khosla写道： 我有一个代码，其中我有一个枚举类似 枚举ADDR {一个= 0; 两个= 1; 三个= 2; }; 后来在代码中，我有一个fu返回一个ADDR类型，它返回一个指向正确值的整数，但我想打印出一个，两个或三个名字。我怎么能这样做，我的例子有很多情况所以不想使用开关语句。 你可以创建一个字符串表示数组： const char * ADDR_strings [] = {" one"，" two"，" three" }; 然后你可以这样做： ADDR addr = get_the_addr（）; std： ：cout<< ADDR_strings [addr]<< std :: endl; " Kapil Khosla" < KH ********* @ yahoo.com> schrieb im Newsbeitrag news：91 ************************** @ posting.google.c om ... 我有一个代码，其中我有一个枚举类似 枚举ADDR {一个= 0; two = 1; 三= 2; }; 后来在代码中，我有一个返回ADDR类型的函数，它返回一个整数指的是正确的价值，但我想打印出一两个或三个名字。我怎么能这样做，我的例子有很多案例所以不想使用切换声明。 谢谢， Kapil 我不知道任何解决方案没有''切换''或者std :: map带插入 为每个枚举器。 在我的应用程序中我使用这样的东西： std： ：ostream的&安培; operator<<（std :: ostream& o，ADDR e） { switch（e） { 案例一：return o<< 一个; 案例二：return o<< 两个; 案例三：return o<< 三; } } 格奥尔格 Hi,I have a code in which I have an enum likeenum ADDR{one = 0;two = 1;three = 2;};Later in code , I have a function that returns an ADDR type, whichreturns an integer referring to the correct value but I want to printout the name one,two or three.How can I do that, my example has a lot of cases so dont want to use aswitch statement.Thanks,Kapil 解决方案"Kapil Khosla" <kh*********@yahoo.com> wrote in messagenews:91**************************@posting.google.c om... Hi, I have a code in which I have an enum like enum ADDR { one = 0; two = 1; three = 2; }; Later in code , I have a function that returns an ADDR type, which returns an integer referring to the correct value but I want to print out the name one,two or three. How can I do that, my example has a lot of cases so dont want to use a switch statement.AFAIK it''s not achievable in your case (with an enum).Why not use a map?With best wishes,J.SchaferKapil Khosla wrote: Hi, I have a code in which I have an enum like enum ADDR { one = 0; two = 1; three = 2; }; Later in code , I have a function that returns an ADDR type, which returns an integer referring to the correct value but I want to print out the name one,two or three. How can I do that, my example has a lot of cases so dont want to use a switch statement.You can make an array of the string representations:const char* ADDR_strings[] = { "one", "two", "three" };Then you can do something like:ADDR addr = get_the_addr();std::cout << ADDR_strings[addr] << std::endl; "Kapil Khosla" <kh*********@yahoo.com> schrieb im Newsbeitragnews:91**************************@posting.google.c om... Hi, I have a code in which I have an enum like enum ADDR { one = 0; two = 1; three = 2; }; Later in code , I have a function that returns an ADDR type, which returns an integer referring to the correct value but I want to print out the name one,two or three. How can I do that, my example has a lot of cases so dont want to use a switch statement. Thanks, KapilI dont'' know any solution without a ''switch'' or a std::map with an insertfor each enumerator.In my applications I use something like this:std::ostream& operator <<( std::ostream& o, ADDR e ){switch( e ){case one: return o << "one";case two: return o << "two";case three: return o << "three";}}Georg 这篇关于枚举！的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！