无法实现具有相同方法名称的两个接口

问题描述

这不起作用：

interface TestInterface
{
    public function testMethod();
}

interface TestInterface2
{
    public function testMethod();
}

class TestClass implements TestInterface, TestInterface2
{

}

给我错误：

这是正确的吗？为什么不允许这样做？对我来说没有意义。

Is that correct? Why is this not allowed? Doesn't make sense to me.

抽象函数也会发生这种情况，例如，如果你实现了一个接口，然后从一个具有抽象函数的类继承它。同名。

This also happens with abstract functions, for example if you implement an interface and then inherit from a class that has an abstract function of the same name.

推荐答案

实现包含具有相同签名的方法的两个接口是没有意义的。

It makes no sense to implement two interfaces containing methods with the same signatures.

编译器无法知道方法是否实际具有相同的目的 - 如果不是，则意味着至少有一个接口不能由您的类实现。

The compiler cannot know if the methods actually have the same purpose - if not, it would mean that at least one of the interfaces cannot be implemented by your class.

示例：

interface IProgram { function execute($what); /* executes the given program */ }
interface ISQLQuery { function execute($what); /* executes the given sql query */ }

class PureAwesomeness implements IProgram, ISQLQuery {
    public function execute($what) { /* execute something.. but what?! */ }
}

如你所见，这两种方法都不可能实现接口 - 并且也不可能从给定的接口调用实际实现该方法的方法。

So as you see, it's impossible to implement the method for both interfaces - and it'd also be impossible to call the method which actually implements the method from a given interface.

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