反应本机可滑动(滑动以删除)未关闭

问题描述

我正在使用来自React-Native-Gesture-Handler的Swipeable合并要在我的页面上删除的滑动.当我按Delete键时，联系人将被删除，但可滑动式保持打开状态.

I'm using Swipeable from React-Native-Gesture-Handler to incorporate swipe to delete on my page.When I press delete, the contact gets deleted however the swipeable remains open.

我希望它在按下后关闭，但我似乎不知道该怎么做.

I want it to close after it gets pressed but I can't seem to figure out how to do it.

这是我的代码:

const RightActions = (progress, dragX) => {
return (
<TouchableOpacity onPress={()=>{DeleteContact(i)}}>
  <View style={[ContactsStyles.rightAction]}>
    <Text style={ContactsStyles.actionText}>Delete</Text>
  </View>
</TouchableOpacity>
)
}

这是我可滑动的地方:

<Swipeable renderRightActions={RightActions} >

     <View style={ContactsStyles.UserContainer}>

         <Text numberOfLines={1} style={[Fonts.Name]}> {obj.firstname} {obj.lastname} </Text>


         {/* Message/Call Container */}
          <View style={ContactsStyles.ImageCont}>
                    {/* Message */}
                    <TouchableOpacity onPress={()  => Communications.text(obj.phone, 'Hey ' + obj.firstname + ', im in need of a Ryde. Are you able to pick me up? This is my current location: ' + location)} >
                      <View style={ContactsStyles.ImageBox}>
                        <Image style={ContactsStyles.Image} source={require('../../assets/icons/message.png')} />
                      </View>
                    </TouchableOpacity>

                    {/* Call */}
                    <TouchableOpacity onPress = {() => Communications.phonecall( obj.phone , true)}>
                      <View style={ContactsStyles.ImageBox}>
                        <Image style={ContactsStyles.Image} source={require('../../assets/icons/phone.png')} />
                      </View>
                    </TouchableOpacity>
                  </View>
                  {/* End of Message/Call Container */}
      </View>
</Swipeable>

推荐答案

您需要使用带有close方法的引用.

You need to use a reference which has a close method on it.

首先定义一个参考

const swipeableRef = useRef(null);

然后将其分配给Swipeable

then assign it to Swipeable

<Swipeable
  ref={swipeableRef}
  renderLeftActions={renderLeftActions}
  onSwipeableLeftOpen={() => handleComplete(item)}
>
    ...
</Swipeable>

然后只需调用close方法

and then just call the close method

const closeSwipeable = () => {
  swipeableRef.current.close();
}

请注意，对于多个可滑动输入，您应该具有多个裁判.

Note, for multiple Swipeables you should have multiple refs.

let row: Array<any> = [];
let prevOpenedRow;

renderItem ({ item, index }) {
  return (
    <Swipeable
      ref={ref => row[index] = ref}
      friction={2}
      leftThreshold={80}
      rightThreshold={40}
      renderRightActions={renderRightActions}
      containerStyle={style.swipeRowStyle}
      onSwipeableOpen={closeRow(index)}
      ...
    >
    ...
    </Swipeable>);
}

closeRow(index) {
  if (prevOpenedRow && prevOpenedRow !== row[index]) {
    prevOpenedRow.close();
  }
  prevOpenedRow = row[index];
}

这篇关于反应本机可滑动(滑动以删除)未关闭的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！