代码点火器动态路由

问题描述

我正在使用代码点火器。

I am using code igniter.

我想做的是

如果页面是

然后我要首先检查一个数据库，看看数据库中是否有 idontexist 。

Then I want to first check a database to see if idontexist is in the database.

如果是，那么我想将用户路由到

If it is then I want to route the user to

我该怎么做？

推荐答案

一种解决方案是在application / core / MY_Router.php中使用您自己的类扩展CI_Router类，然后在类中复制方法_set_routing（）。
您的更改将在包含route.php文件并将其设置为$ this-> routes属性之后进行，您可以添加自定义路由。

One solution would be to extend the CI_Router class with your own in application/core/MY_Router.php and just copy the method _set_routing() in your class.Your changes would go somewhere after routes.php file is included and set to $this->routes property, you can add your custom routes.

include(APPPATH.'config/routes'.EXT);
...
$this->routes = ( ! isset($route) OR ! is_array($route)) ? array() : $route;
unset($route);

//Get your custom routes:
$your_routes = $this->_get_custom_routes();
foreach($your_routes as $custom_route)
{
    $this->routes[$custom_route['your_regex_match']] = $custom_route['controller'].'/'.$custom_route['action'];
}

当然您可能不需要，但是我希望它能给您一些想法。
这样，您可以添加自定义路由，并且由于必须从数据库中获取它们，因此可以考虑对其进行缓存以提高速度。

Of course you might not need this, but I hope it gives you some idea.This way you can add custom routes and since you will have to fetch them from database, consider caching them for better speed.

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