[Proposal]具有默认值的命名和可选参数

本文介绍了[Proposal]具有默认值的命名和可选参数的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 29岁程序员，3月因学历无情被辞！ 几个月前我有类似的想法，但现在这个需要 没有改变clr，相对容易实现并且会很棒 除了C＃3.0 :) 所以我们走了...... 为了让事情更简单，更易读，我会做所有默认参数 命名参数，这样你就可以自己决定要传递哪一个和 哪个不是，而不是依靠大量重叠的方法 希望为你提供最好的重载，例如Image.DrawImage 方法有20个重载。 我提出如下语法： public void Open（字符串路径，AccessMode模式= AccessMode.Read， int bufferSize = 1024） { // ... } 如您所见，path是一个常规参数，不能省略，而 Mode和BufferSize提供默认值，可以是omitt当调用 方法时编辑。 命名参数只能在所有常规参数后面声明，如果 你有params参数（变量参数列表）必须在参数列表末尾的 处声明。虽然你可以省略命名参数，如果你传递了它们，它们应该按照声明的相同顺序出现 更好的可读性。 您可以调用如下示例方法： Open（" text.txt"，$ mode = AccessMode.Write，$ bufferSize = 512）; Open（" text.txt"，$ bufferSize = 512）; Open（" text.txt"，$ mode = AccessMode.Write）; 打开（" text.txt"）; 请注意，$ sign必须出现在所有命名参数之前，以便你 有没有命名与调用者上下文中的其他变量冲突。 另外，没有更多的那个方法具有相同的名称和 相同的常规参数避免含糊不清，所以： Foo（int i，string a =""）; Foo（int i，double f = 1.0f） ; 不允许，因为无法解析调用Foo（100）。 如何运作？ ---------------------------- 以下方法： public void Open（字符串路径，AccessMode模式= AccessMode.Read，int bufferSize = 1024） { // ... } 将生成以下代码： public struct OpenParams { 公共AccessMode模式; public int bufferSize; //因为我们不能在结构中使用无参数的ctors public static OpenParams DefaultValues { get { OpenParams instance = new OpenParams（）; instance.mode = AccessMode.Read; instance.bufferSize = 1024; 返回实例; } } } public void Open（ string path，ref OpenParams parms） { // ... } 和电话： Open（" text.txt"，$ bufferSize = 512 ）; 编译为： OpenParams parms = OpenParams.DefaultValues; parms.bufferSize = 512 ; 开放（" text.txt"，ref parms）; 那么你怎么看？这只是另一个愚蠢的想法，还是值得为csharp程序员付出的努力和价值？ 解决方案 mode = AccessMode.Write， bufferSize = 512）; Open（" text.txt"， bufferSize = 512）; Open（" text.txt"， I got a similar idea a couple of months ago, but now this one will requireno change to the clr, is relatively easy to implement and would be a greataddition to C# 3.0 :)so here we go..To make things simpler and better readable I''d make all default parametersnamed parameters so that you can decide for yourself which one to pass andwhich not, rather than relying on massively overlaoded methods whichhopefully provide the best overload for you, for example the Image.DrawImagemethod has 20 overloads.I propose a syntax like the following:public void Open(string path, AccessMode mode = AccessMode.Read,int bufferSize=1024){// ...}As you can see, path is a regular parameter which cannot be omitted, whereasMode and BufferSize provide default values and can be omitted when callingthe method.Named parameters can only be declared behind all regular parameters and ifyou have params parameters (variable parameterlist) is must be declared atthe end of the parameterlist. Although you can omit the named parameters ifyou pass them they should appear in the same order as they were declared forbetter readability.You could call the example method like the following:Open("text.txt", $mode=AccessMode.Write, $bufferSize=512);Open("text.txt", $bufferSize=512);Open("text.txt", $mode=AccessMode.Write);Open("text.txt");Note that an $ sign has to appear before all named parameter so that youhave no naming conflicts with other variables in the callers context.Additionally there can not be more that one method with the same name andthe same regular parameters to avoid ambiguity, so:Foo(int i, string a="");Foo(int i, double f=1.0f);Would not be allowed because the call Foo(100) could not be resolved.How will it work?----------------------------the following method:public void Open(string path, AccessMode mode = AccessMode.Read, intbufferSize=1024){// ...}would generate the following code:public struct OpenParams{public AccessMode mode;public int bufferSize;// because we cannot have parameterless ctors in structspublic static OpenParams DefaultValues{get{OpenParams instance = new OpenParams();instance.mode = AccessMode.Read;instance.bufferSize=1024;return instance;}}}public void Open(string path, ref OpenParams parms){// ...}and the call:Open("text.txt", $bufferSize=512);is compiled as:OpenParams parms = OpenParams.DefaultValues;parms.bufferSize=512;Open("text.txt", ref parms);So what do you think? Is it just another stupid idea or may it be worth theeffort and valueable for csharp programmers? 解决方案 mode=AccessMode.Write,bufferSize=512);Open("text.txt",bufferSize=512);Open("text.txt", 这篇关于[Proposal]具有默认值的命名和可选参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！ 上岸，阿里云！