将8位ASCII转换为6位

问题描述

我正在尝试获取一个char并将其转换为6位二进制文​​件.知道如何在C#中做到这一点.这是我到目前为止所拥有的.

Hi,

I am trying to take a char and convert it to 6 bit binary. Any idea how one can do this in C#. Here is what I have so far.

char c = '1';
int i = Convert.ToInt32(c);
while (i > 40)
    i -= 8;
Console.WriteLine(Convert.ToString(i, 2));
Console.ReadLine();

结果为"100001"，应为"000001".

有什么想法吗?

The result for this is ''100001'', where it should be ''000001''.

Any ideas?

推荐答案

private string ascii2ais(string p)
        {
            StringBuilder sb = new StringBuilder();

            char[] chars = p.ToCharArray();
            foreach (char c in chars)
            {
                int i = Convert.ToInt32(c);
                i -= 48;
                if (i>40)
                {
                    i -= 8;
                }

                string sixBit = Convert.ToString(i, 2).PadLeft(6, '0');
                sb.Append(sixBit + " ");
            }

            return sb.ToString();

        }

这应该可以解决问题.至少我尝试过将14eG转换为``000001 000100 101101 010111''

This should do the trick. At least I tried that 14eG is translated to ''000001 000100 101101 010111''

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