如何在Python中修复'TypeError:'function'类型的参数不可迭代'

问题描述

我正在制作一个django应用程序，该应用程序能够发送和接收电子邮件.对于django应用程序，我正在为views.py编写代码.运行文件后，我陷入了这个错误.这是我的Django应用程序中的views.py

I was making a django app which would be able to send and receive emails. For the django app I was writing the code for views.pyAfter I ran the file, I got stuck with this error.This is the views.py from my django app

from django.shortcuts import render
from django.contrib import messages
from django.core.mail import send_mail
#from demoapp.form import ContactForm


# Create your views here.

def index(request):
    return render(request,'index.html',{'page':'home'})


def contact(request):
    try:
        if request.method == 'POST':
            form = ContactForm(request.POST)
            if form.is_valid():
                send_mail(form.cleaned_data)
                messages.success(request,'Your message is successfully submitted')

        else:
            form = ContactForm()

    except:
        messages.error(request,'contact.html',{'page':'contact','form':form})

def clear(request):
    form = ContactForm()
    messages.error(request,'Fields Cleared')
    return render(request,'contact.html',{'page':'contact','form':form})

Urls.py 该urls.py来自django项目.我尚未为我的应用创建任何urls.py.

Urls.pyThis urls.py is from the django project. I havent created any urls.py for my app.

from django.contrib import admin
from django.urls import path
from django.conf.urls import url
from demoapp.views import index,about,contact,clear
urlpatterns = [
    path('admin/', admin.site.urls),
    url(r'^$' , index , name=index),
    url(r'^about/$' , about , name=about),
    url(r'^contact/$' , contact , name=contact),
    url(r'^clear/$' , clear , name=clear),


]

运行python3 manage.py runserver之后，出现以下错误

After I run python3 manage.py runserver I get the following error

Watching for file changes with StatReloader
Performing system checks...

Exception in thread Thread-1:
Traceback (most recent call last):
  File "/usr/lib/python3.6/threading.py", line 916, in _bootstrap_inner
    self.run()
  File "/usr/lib/python3.6/threading.py", line 864, in run
    self._target(*self._args, **self._kwargs)
  File "/usr/local/lib/python3.6/dist-packages/django/utils/autoreload.py", line 54, in wrapper
    fn(*args, **kwargs)
  File "/usr/local/lib/python3.6/dist-packages/django/core/management/commands/runserver.py", line 117, in inner_run
    self.check(display_num_errors=True)
  File "/usr/local/lib/python3.6/dist-packages/django/core/management/base.py", line 390, in check
    include_deployment_checks=include_deployment_checks,
  File "/usr/local/lib/python3.6/dist-packages/django/core/management/base.py", line 377, in _run_checks
    return checks.run_checks(**kwargs)
  File "/usr/local/lib/python3.6/dist-packages/django/core/checks/registry.py", line 72, in run_checks
    new_errors = check(app_configs=app_configs)
  File "/usr/local/lib/python3.6/dist-packages/django/core/checks/urls.py", line 13, in check_url_config
    return check_resolver(resolver)
  File "/usr/local/lib/python3.6/dist-packages/django/core/checks/urls.py", line 23, in check_resolver
    return check_method()
  File "/usr/local/lib/python3.6/dist-packages/django/urls/resolvers.py", line 399, in check
    messages.extend(check_resolver(pattern))
  File "/usr/local/lib/python3.6/dist-packages/django/core/checks/urls.py", line 23, in check_resolver
    return check_method()
  File "/usr/local/lib/python3.6/dist-packages/django/urls/resolvers.py", line 325, in check
    warnings = self._check_pattern_name()
  File "/usr/local/lib/python3.6/dist-packages/django/urls/resolvers.py", line 333, in _check_pattern_name
    if self.pattern.name is not None and ":" in self.pattern.name:
TypeError: argument of type 'function' is not iterable

推荐答案

您的名称不是字符串，而是对视图 functions 的引用.您应该改用字符串，例如:

Your names are not strings, but references to the view functions. You should use strings instead, like:

urlpatterns = [
    path('admin/', admin.site.urls),
    url(r'^$' , index , name='index'),
    url(r'^about/$' , about , name='about'),
    url(r'^contact/$' , contact , name='contact'),
    url(r'^clear/$' , clear , name='clear'),
]

因此，我们在这里使用字符串文字 'index'代替仅引用视图函数的 index 标识符.

So we here use a string literal 'index' instead of the index identifier, which just refers to the view function.

这篇关于如何在Python中修复'TypeError:'function'类型的参数不可迭代'的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！