问题描述
我有一个Java项目，该项目完全由javen/integration测试组成，由maven管理.依赖项之一是zip存档，运行测试时，我希望其内容可在classpath上找到.由于 maven不会将zip依赖项的内容放在类路径上我认为这是个骇人的解决方法.我将zip归档文件解压缩到一个临时目录中，然后将结果目录之一复制到/test-classes文件夹中.我还必须使clean步骤删除temp目录.这是pom的相关部分:
I have a Java project entirely consisting of junit/integration tests which is managed by maven. One of the dependencies is a zip archive, the contents of which I would like to be available on the classpath when the tests are run. Since maven does not put the content of a zip dependency on the classpath I have had to come up with what I consider to be a hacky workaround. I unpack the zip archive to a temp directory then copy one of the resulting directories into the /test-classes folder. I also had to make the clean step delete the temp directory. Here are the relevant parts of the pom:
<groupId>com.my.package</groupId>
<artifactId>test-project</artifactId>
<version>0.0.1-SNAPSHOT</version>
<name>My Test Project</name>
<properties>
<config.artifactId>environment-dev</config.artifactId>
<config.version>2.0.8-SNAPSHOT</config.version>
<tempDir>${project.basedir}/temp</tempDir>
</properties>
<build>
<plugins>
...
<!-- clean out our custom temp directory as well as the default dir during clean phase-->
<plugin>
<artifactId>maven-clean-plugin</artifactId>
<version>2.3</version>
<configuration>
<filesets>
<fileset>
<directory>${tempDir}</directory>
</fileset>
</filesets>
</configuration>
</plugin>
<!-- since the config dependency is a zip it does not get added to the classpath. So we extract
it to a temp dir, then copy the content we need into a directory on the classpath -->
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.8</version>
<executions>
<execution>
<id>unpack-config</id>
<phase>compile</phase>
<goals><goal>unpack-dependencies</goal></goals>
<configuration>
<includeGroupIds>com.my.package.config</includeGroupIds>
<includeArtifactIds>${config.artifactId}</includeArtifactIds>
<includeClassifiers>config</includeClassifiers>
<outputDirectory>${tempDir}</outputDirectory>
</configuration>
</execution>
</executions>
</plugin>
<!-- copy the content of the zip file that we extracted into a directory on the classpath -->
<plugin>
<artifactId>maven-resources-plugin</artifactId>
<version>2.6</version>
<executions>
<execution>
<phase>compile</phase>
<goals><goal>copy-resources</goal></goals>
<configuration>
<outputDirectory>${project.build.directory}/test-classes/TargetDir</outputDirectory>
<resources>
<resource>
<directory>${tempDir}/${config.artifactId}-${config.version}/TargetDir</directory>
<filtering>true</filtering>
</resource>
</resources>
</configuration>
</execution>
</executions>
</plugin>
</plugins>
</build>
<dependencies>
...
<dependency>
<groupId>com.my.package.config</groupId>
<artifactId>${config.artifactId}</artifactId>
<version>${config.version}</version>
<classifier>config</classifier>
<type>zip</type>
</dependency>
</dependencies>
必须有一种更好的方法.
我可以强制Maven将zip文件当作一个jar来对待吗?我提供的链接非常诱人，暗示这曾经可能实现，但是我在文档中找不到任何相关的内容.这似乎很简单，我真的希望我只是在某个地方错过了config参数.谁能建议一种更好的方法来将zip依赖项的内容放到类路径中?
Can I force maven to treat the zip file as if it were a jar? The link I provided has a tantalising hint that this might once have been possible, but I can't find anything relevant in the documentation. This seems like such a simple thing to be able to do, I really hope I've just missed a config parameter somewhere. Can anyone suggest a better way of getting the content of a zip dependency onto the classpath?
推荐答案
我将把依赖关系解压缩到target目录的子目录中，然后将该目录添加到配置.
I would unzip the dependency into a subdirectory of the target directory and add that directory to the additionalClasspathElements configuration of the surefire plugin.
<properties>
<config.artifactId>environment-dev</config.artifactId>
<config.version>2.0.8-SNAPSHOT</config.version>
<unzipDir>${project.build.directory}/addTestClasspath</unzipDir>
</properties>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-dependency-plugin</artifactId>
<version>2.8</version>
<executions>
<execution>
<id>unpack-config</id>
<phase>compile</phase>
<goals><goal>unpack-dependencies</goal></goals>
<configuration>
<includeGroupIds>com.my.package.config</includeGroupIds>
<includeArtifactIds>${config.artifactId}</includeArtifactIds>
<includeClassifiers>config</includeClassifiers>
<outputDirectory>${unzipDir}</outputDirectory>
</configuration>
</execution>
</executions>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-surefire-plugin</artifactId>
<version>2.17</version>
<configuration>
<additionalClasspathElements>
<additionalClasspathElement>${unzipDir}</additionalClasspathElement>
</additionalClasspathElements>
</configuration>
</plugin>
</plugins>
</build>
在这种情况下，您可以省略clean插件配置，因为所有内容都在target文件夹下，默认情况下该文件夹将由clean插件删除.
In this case you can omit the clean plugin config because everything is under the target folder which will be deleted by the clean plugin by default.
遗憾的是，此配置仅在命令行上有效，而不能在eclipse中使用，因为m2e插件不支持additionalClasspathElement.请参见jira问题 MNGECLIPSE-1213
Sadly this configuration does only work on the command line and not within eclipse, because the m2e plugin does not honor the additionalClasspathElement. See the jira issue MNGECLIPSE-1213
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